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Have you solved systems of linear equations before? If so, do you have any ideas of where to start?

no i have idea

no idea**

Step 1: Which equation are you choosing from: ?
4x - y = -11
2x + 3y = 5

does it matter which one i choose

Nope. It does not matter.

Which equation is the easiest to solve for y?

I'd go with the easiest and i'll choose the first equation.

2x+3y=5
there is no negatives so its probably easier to solve

Okay, we'll go with that.

oops lol we can go with yours

Okay.

Makes sense?

what is y equal to now?

14x ? im sorry im so confused on this, and my teacher isnt responding

idk what to do

What does step 2 say?

y=11+4x
Our second equation is
2x+3y=5
\(\large 2x+3(11+4x)=5 \)

2x+33+12x=5 ? or do you not use distributive property

Yes, you already distributed it

how do i solve that? add or multiply?

so 14x

oh yeah sorry

yes, so now we have
14x + 33 = 5
subtract 33 from each sign

*from each side

-19=-28

am i supposed to subtract 33 from 33 too or no

yes

14x = -28
divide both sides by 14

x=-2

-2

no i dont understand

-8 - y = -11
add 8 to both sides, what do you get?

-y=-19

add, not subtract
-11 + 8 = ?

-3

right, so
-y = -3
what is y?

boom, we're done
x = -2 and y = 3
our solution is (-2,3)

thanks