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anonymous
 one year ago
!PHYSICS! Anyone willing to share their modest mental qualities you are welcomeXD I will give owl bucks
anonymous
 one year ago
!PHYSICS! Anyone willing to share their modest mental qualities you are welcomeXD I will give owl bucks

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. Since each light bulb carries a resistance of 120 Ω, the total resistance of series circuit is calculated as follows, Rs=120Ω+120Ω+120Ω+120Ω+120Ω=600Ω The total resistance in this series circuit is therefore 6.0*10^2. On the other hand, if the light bulbs were placed in parallel manner, then the total resistance will be, 1/R=1/120+1/120+1/120+1/120+1/120 Isolating for R 1=R(1/120+1/120+1/120+1/120+1/120) 1=0.04166R R=24.000 Therefore the total resistance in parallel circuit is 24Ω 2. From the diagram, junctions of the circuit are a. H and B b. Loops of this circuit consist of the loop ABCH and BCHDFG 1. The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V2.5V1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answers owe thanks to the following questions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Six 120 Ω light bulbs are connected in series. What is the total resistance of this circuit? What would be the total resistance if they were connected in parallel?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is a disappointing result @abb0t

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Good try though Mr. Boo

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Perhaps @pooja195 can help since she seems to be so obsequious about medals.

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0@abb0t have nothing to say? DONT SAY IT. I havent taken physics yet so i cant help sorry.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@pooja195 He was jokingXD

pooja195
 one year ago
Best ResponseYou've already chosen the best response.050 tags http://prntscr.com/84lxqy NOT a joke hes being annoying

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439458995536:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What a beautiful diagram I have ever seen!

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Those are in series. Yes.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's undoubtedly the series diagram on the bus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you serial @abbot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now you both taking the piss!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's a british slang

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this too simple a problem for @abott?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There are genuine people that need help, so I will leave this problem to @abb0t

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0Just add them all up in series. You would add them inversely if they were parallel

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For a second question for 99 smiling guy I summon you guys to kick me on this diagram

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Junctions, branches, and loops are my objectives. Give me the coordinates

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Physicist is here!!!

ali2x2
 one year ago
Best ResponseYou've already chosen the best response.0i have no idea ive never taken physics

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the first answer is right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Second question I need to identify branches, junctions as well as loops from the diagram

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but they are kind of complicated for my immature self

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I forgot to include the branches but whatever

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1what we have to compute for question #2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No we just need to name the points separately for junctions, branches, and loops

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can simplify your circuit like this: dw:1439571599988:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so junctions are points where more than 3 lines are intersecting ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! at least 3 lines

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So for junction it's safe to say B and H

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The branches are extensions of junction right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it's safe to say they are C and A right

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes A and c are branches

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1also D, F and G are branches

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Great! Now loops are flowing circuits in a circular manner so they are as my answer says "Loops of this circuit consist of the loop ABCH and BCHDFG" or do I use shorter form of saying that

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is correct, we have 2 loops ABCH and BCHGFD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. That's nice. What about the question 3 with the diagram where I need to look for the missing Voltage?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1by definition, we say that a loop is a continuous path of conductors

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V2.5V1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1first circuit, we have: 2.5 +1.1 +V= 60, where V is the missing voltage

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so you are right!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I assume the second problem is very identical to the first as well?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1second circuit: we can write this: 4.2 +5.4 +7.5 = Vt

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so you are right again!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nice! The rules of sig figs don't apply to this particular addition problem does it?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more explanation: in both circuits we have applied this subsequent law, which is valid for an electrostatic field: \[\Large {\text{rot }}{\mathbf{E}} = {\mathbf{0}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0When all the electrical potentials are summed it results in zero

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1in other words the integral of the electric field along a circuit, or a loop, has to be equal to zero

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1when you are doing a computation for a single loop

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more precisely, for a single loop, the algebraic sum of the voltage drops (along the resistance) and the voltage of batteries, has to be equal to zero that is the second law of Kirchhoff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where did you complete your physics degree?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am looking to do physics degree too after medicine

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1at the University of Pisa, here in Italy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe I should have taken physics instead XD

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1ok! Physics is a good choice, congrats!! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you doing your thesis for PhD yet?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1no, I have not the PhD title

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I heard that with PhD in physics you can make like 200 grands working for national search institutions and stuff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so physicists are richer than doctors if they are really good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and physicists are bunch of smartest people on earth

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1at the moment I have no job, lol!

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1I think that a physicist is a man who tries to understand our universe

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1or more simply all what is around us

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah! Physicist is a revolutionist

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1at the moment please think about to get your degree in medicine, and after that you can think about physics, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can work as a doctor and still go to university for physics.
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