## anonymous one year ago !PHYSICS! Anyone willing to share their modest mental qualities you are welcomeXD I will give owl bucks

1. abb0t

No.

2. anonymous

1. Since each light bulb carries a resistance of 120 Ω, the total resistance of series circuit is calculated as follows, Rs=120Ω+120Ω+120Ω+120Ω+120Ω=600Ω The total resistance in this series circuit is therefore 6.0*10^2. On the other hand, if the light bulbs were placed in parallel manner, then the total resistance will be, 1/R=1/120+1/120+1/120+1/120+1/120 Isolating for R 1=R(1/120+1/120+1/120+1/120+1/120) 1=0.04166R R=24.000 Therefore the total resistance in parallel circuit is 24Ω 2. From the diagram, junctions of the circuit are a. H and B b. Loops of this circuit consist of the loop ABCH and BCHDFG 1. The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V-2.5V-1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

3. anonymous

My answers owe thanks to the following questions

4. anonymous

Six 120 Ω light bulbs are connected in series. What is the total resistance of this circuit? What would be the total resistance if they were connected in parallel?

5. anonymous

that is a disappointing result @abb0t

6. anonymous

Good try though Mr. Boo

7. anonymous

XDXDXD

8. abb0t

Perhaps @pooja195 can help since she seems to be so obsequious about medals.

9. pooja195

@abb0t have nothing to say? DONT SAY IT. I havent taken physics yet so i cant help sorry.

10. anonymous

OMG, no diagrams?

11. anonymous

@pooja195 He was jokingXD

12. pooja195

50 tags http://prntscr.com/84lxqy NOT a joke hes being annoying

13. anonymous

|dw:1439458995536:dw|

14. anonymous

What a beautiful diagram I have ever seen!

15. abb0t

Those are in series. Yes.

16. anonymous

That's undoubtedly the series diagram on the bus

17. anonymous

Are you serial @abbot

18. anonymous

now you both taking the piss!

19. anonymous

That's a british slang

20. anonymous

Is this too simple a problem for @abott?

21. anonymous

There are genuine people that need help, so I will leave this problem to @abb0t

22. abb0t

Just add them all up in series. You would add them inversely if they were parallel

23. anonymous

For a second question for 99 smiling guy I summon you guys to kick me on this diagram

24. anonymous

Junctions, branches, and loops are my objectives. Give me the coordinates

25. anonymous

Physicist is here!!!

26. anonymous

@Michele_Laino

27. ali2x2

i have no idea ive never taken physics

28. Michele_Laino

the first answer is right!

29. anonymous

Yay!

30. anonymous

Second question I need to identify branches, junctions as well as loops from the diagram

31. anonymous

but they are kind of complicated for my immature self

32. anonymous

I forgot to include the branches but whatever

33. Michele_Laino

what we have to compute for question #2?

34. anonymous

No we just need to name the points separately for junctions, branches, and loops

35. Michele_Laino

we can simplify your circuit like this: |dw:1439571599988:dw|

36. anonymous

so junctions are points where more than 3 lines are intersecting ?

37. Michele_Laino

yes! at least 3 lines

38. anonymous

So for junction it's safe to say B and H

39. Michele_Laino

yes!

40. anonymous

The branches are extensions of junction right?

41. Michele_Laino

yes! I think so

42. anonymous

So it's safe to say they are C and A right

43. Michele_Laino

yes A and c are branches

44. Michele_Laino

also D, F and G are branches

45. anonymous

Great! Now loops are flowing circuits in a circular manner so they are as my answer says "Loops of this circuit consist of the loop ABCH and BCHDFG" or do I use shorter form of saying that

46. anonymous

May I ask why?

47. Michele_Laino

it is correct, we have 2 loops ABCH and BCHGFD

48. anonymous

Ok. That's nice. What about the question 3 with the diagram where I need to look for the missing Voltage?

49. Michele_Laino

by definition, we say that a loop is a continuous path of conductors

50. anonymous

The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V-2.5V-1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

51. anonymous

That's nice to know

52. Michele_Laino

first circuit, we have: 2.5 +1.1 +V= 60, where V is the missing voltage

53. Michele_Laino

so you are right!

54. anonymous

Yay!

55. anonymous

I assume the second problem is very identical to the first as well?

56. Michele_Laino

second circuit: we can write this: 4.2 +5.4 +7.5 = Vt

57. Michele_Laino

so you are right again!

58. anonymous

Nice! The rules of sig figs don't apply to this particular addition problem does it?

59. Michele_Laino

more explanation: in both circuits we have applied this subsequent law, which is valid for an electrostatic field: $\Large {\text{rot }}{\mathbf{E}} = {\mathbf{0}}$

60. anonymous

When all the electrical potentials are summed it results in zero

61. Michele_Laino

in other words the integral of the electric field along a circuit, or a loop, has to be equal to zero

62. Michele_Laino

when you are doing a computation for a single loop

63. anonymous

Wow

64. Michele_Laino

more precisely, for a single loop, the algebraic sum of the voltage drops (along the resistance) and the voltage of batteries, has to be equal to zero that is the second law of Kirchhoff

65. anonymous

Where did you complete your physics degree?

66. anonymous

I am looking to do physics degree too after medicine

67. Michele_Laino

at the University of Pisa, here in Italy

68. anonymous

Maybe I should have taken physics instead XD

69. Michele_Laino

ok! Physics is a good choice, congrats!! :)

70. anonymous

Are you doing your thesis for PhD yet?

71. Michele_Laino

no, I have not the PhD title

72. anonymous

I heard that with PhD in physics you can make like 200 grands working for national search institutions and stuff

73. anonymous

so physicists are richer than doctors if they are really good

74. anonymous

and physicists are bunch of smartest people on earth

75. Michele_Laino

at the moment I have no job, lol!

76. Michele_Laino

I think that a physicist is a man who tries to understand our universe

77. Michele_Laino

or more simply all what is around us

78. anonymous

Yeah! Physicist is a revolutionist

79. Michele_Laino

at the moment please think about to get your degree in medicine, and after that you can think about physics, right?

80. anonymous

Yeah I think so.

81. anonymous

I can work as a doctor and still go to university for physics.

82. anonymous

To be like you

83. Michele_Laino

thanks!! :)