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anonymous

  • one year ago

!PHYSICS! Anyone willing to share their modest mental qualities you are welcomeXD I will give owl bucks

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  1. abb0t
    • one year ago
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    No.

  2. anonymous
    • one year ago
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    1. Since each light bulb carries a resistance of 120 Ω, the total resistance of series circuit is calculated as follows, Rs=120Ω+120Ω+120Ω+120Ω+120Ω=600Ω The total resistance in this series circuit is therefore 6.0*10^2. On the other hand, if the light bulbs were placed in parallel manner, then the total resistance will be, 1/R=1/120+1/120+1/120+1/120+1/120 Isolating for R 1=R(1/120+1/120+1/120+1/120+1/120) 1=0.04166R R=24.000 Therefore the total resistance in parallel circuit is 24Ω 2. From the diagram, junctions of the circuit are a. H and B b. Loops of this circuit consist of the loop ABCH and BCHDFG 1. The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V-2.5V-1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

  3. anonymous
    • one year ago
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    My answers owe thanks to the following questions

  4. anonymous
    • one year ago
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    Six 120 Ω light bulbs are connected in series. What is the total resistance of this circuit? What would be the total resistance if they were connected in parallel?

  5. anonymous
    • one year ago
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    that is a disappointing result @abb0t

  6. anonymous
    • one year ago
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    Good try though Mr. Boo

  7. anonymous
    • one year ago
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    XDXDXD

  8. abb0t
    • one year ago
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    Perhaps @pooja195 can help since she seems to be so obsequious about medals.

  9. pooja195
    • one year ago
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    @abb0t have nothing to say? DONT SAY IT. I havent taken physics yet so i cant help sorry.

  10. anonymous
    • one year ago
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    OMG, no diagrams?

  11. anonymous
    • one year ago
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    @pooja195 He was jokingXD

  12. pooja195
    • one year ago
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    50 tags http://prntscr.com/84lxqy NOT a joke hes being annoying

  13. anonymous
    • one year ago
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    |dw:1439458995536:dw|

  14. anonymous
    • one year ago
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    What a beautiful diagram I have ever seen!

  15. abb0t
    • one year ago
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    Those are in series. Yes.

  16. anonymous
    • one year ago
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    That's undoubtedly the series diagram on the bus

  17. anonymous
    • one year ago
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    Are you serial @abbot

  18. anonymous
    • one year ago
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    now you both taking the piss!

  19. anonymous
    • one year ago
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    That's a british slang

  20. anonymous
    • one year ago
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    Is this too simple a problem for @abott?

  21. anonymous
    • one year ago
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    There are genuine people that need help, so I will leave this problem to @abb0t

  22. abb0t
    • one year ago
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    Just add them all up in series. You would add them inversely if they were parallel

  23. anonymous
    • one year ago
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    For a second question for 99 smiling guy I summon you guys to kick me on this diagram

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  24. anonymous
    • one year ago
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    Junctions, branches, and loops are my objectives. Give me the coordinates

  25. anonymous
    • one year ago
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    Physicist is here!!!

  26. anonymous
    • one year ago
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    @Michele_Laino

  27. ali2x2
    • one year ago
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    i have no idea ive never taken physics

  28. Michele_Laino
    • one year ago
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    the first answer is right!

  29. anonymous
    • one year ago
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    Yay!

  30. anonymous
    • one year ago
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    Second question I need to identify branches, junctions as well as loops from the diagram

  31. anonymous
    • one year ago
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    but they are kind of complicated for my immature self

  32. anonymous
    • one year ago
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    I forgot to include the branches but whatever

  33. Michele_Laino
    • one year ago
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    what we have to compute for question #2?

  34. anonymous
    • one year ago
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    No we just need to name the points separately for junctions, branches, and loops

  35. Michele_Laino
    • one year ago
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    we can simplify your circuit like this: |dw:1439571599988:dw|

  36. anonymous
    • one year ago
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    so junctions are points where more than 3 lines are intersecting ?

  37. Michele_Laino
    • one year ago
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    yes! at least 3 lines

  38. anonymous
    • one year ago
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    So for junction it's safe to say B and H

  39. Michele_Laino
    • one year ago
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    yes!

  40. anonymous
    • one year ago
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    The branches are extensions of junction right?

  41. Michele_Laino
    • one year ago
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    yes! I think so

  42. anonymous
    • one year ago
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    So it's safe to say they are C and A right

  43. Michele_Laino
    • one year ago
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    yes A and c are branches

  44. Michele_Laino
    • one year ago
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    also D, F and G are branches

  45. anonymous
    • one year ago
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    Great! Now loops are flowing circuits in a circular manner so they are as my answer says "Loops of this circuit consist of the loop ABCH and BCHDFG" or do I use shorter form of saying that

  46. anonymous
    • one year ago
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    May I ask why?

  47. Michele_Laino
    • one year ago
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    it is correct, we have 2 loops ABCH and BCHGFD

  48. anonymous
    • one year ago
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    Ok. That's nice. What about the question 3 with the diagram where I need to look for the missing Voltage?

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  49. Michele_Laino
    • one year ago
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    by definition, we say that a loop is a continuous path of conductors

  50. anonymous
    • one year ago
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    The electrical potential difference for the first diagram is calculated by reasoning with the fact that in series circuits voltages will be distributed in such ways that add up to the voltage at the battery depending on the resistance on each load. Therefore, Delta V2=60V-2.5V-1.1=56.4V Therefore the voltage at Delta V2 is 56.4V Since the voltage can be added to find the voltage at battery, 5.4V+7.5V+4.2V=17.1V Therefore the electrical potential difference at battery is 17.1V

  51. anonymous
    • one year ago
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    That's nice to know

  52. Michele_Laino
    • one year ago
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    first circuit, we have: 2.5 +1.1 +V= 60, where V is the missing voltage

  53. Michele_Laino
    • one year ago
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    so you are right!

  54. anonymous
    • one year ago
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    Yay!

  55. anonymous
    • one year ago
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    I assume the second problem is very identical to the first as well?

  56. Michele_Laino
    • one year ago
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    second circuit: we can write this: 4.2 +5.4 +7.5 = Vt

  57. Michele_Laino
    • one year ago
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    so you are right again!

  58. anonymous
    • one year ago
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    Nice! The rules of sig figs don't apply to this particular addition problem does it?

  59. Michele_Laino
    • one year ago
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    more explanation: in both circuits we have applied this subsequent law, which is valid for an electrostatic field: \[\Large {\text{rot }}{\mathbf{E}} = {\mathbf{0}}\]

  60. anonymous
    • one year ago
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    When all the electrical potentials are summed it results in zero

  61. Michele_Laino
    • one year ago
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    in other words the integral of the electric field along a circuit, or a loop, has to be equal to zero

  62. Michele_Laino
    • one year ago
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    when you are doing a computation for a single loop

  63. anonymous
    • one year ago
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    Wow

  64. Michele_Laino
    • one year ago
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    more precisely, for a single loop, the algebraic sum of the voltage drops (along the resistance) and the voltage of batteries, has to be equal to zero that is the second law of Kirchhoff

  65. anonymous
    • one year ago
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    Where did you complete your physics degree?

  66. anonymous
    • one year ago
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    I am looking to do physics degree too after medicine

  67. Michele_Laino
    • one year ago
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    at the University of Pisa, here in Italy

  68. anonymous
    • one year ago
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    Maybe I should have taken physics instead XD

  69. Michele_Laino
    • one year ago
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    ok! Physics is a good choice, congrats!! :)

  70. anonymous
    • one year ago
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    Are you doing your thesis for PhD yet?

  71. Michele_Laino
    • one year ago
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    no, I have not the PhD title

  72. anonymous
    • one year ago
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    I heard that with PhD in physics you can make like 200 grands working for national search institutions and stuff

  73. anonymous
    • one year ago
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    so physicists are richer than doctors if they are really good

  74. anonymous
    • one year ago
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    and physicists are bunch of smartest people on earth

  75. Michele_Laino
    • one year ago
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    at the moment I have no job, lol!

  76. Michele_Laino
    • one year ago
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    I think that a physicist is a man who tries to understand our universe

  77. Michele_Laino
    • one year ago
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    or more simply all what is around us

  78. anonymous
    • one year ago
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    Yeah! Physicist is a revolutionist

  79. Michele_Laino
    • one year ago
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    at the moment please think about to get your degree in medicine, and after that you can think about physics, right?

  80. anonymous
    • one year ago
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    Yeah I think so.

  81. anonymous
    • one year ago
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    I can work as a doctor and still go to university for physics.

  82. anonymous
    • one year ago
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    To be like you

  83. Michele_Laino
    • one year ago
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    thanks!! :)

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