Solve: 16x2 − 81 = 0. x = 4, 9 x = −4, −9 x = 9 over 4, x = −9 over 4 x = 81 over 16, x = −81 over 16

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Solve: 16x2 − 81 = 0. x = 4, 9 x = −4, −9 x = 9 over 4, x = −9 over 4 x = 81 over 16, x = −81 over 16

Mathematics
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hint: 16x^2 - 81 = A^2 - B^2 can you tell me what A and B are?
@pooja195 can help!
A and B are the numbers

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Other answers:

right, but which numbers? 16x^2 - 81 = A^2 - B^2 what is A = ?
- 9 over 4?
... what? |dw:1439571060249:dw|
so, if A^2 = 16x^2, what is A?
A is 16x^2
nope, not quite... A^2 = 16x^2 A = ?
A is 16^2
nope, try one more time... A^2 = 16x^2 A = square root of A^2 = ?
ITS 100
?
what is the square root of 16x^2?
Well 256 is what 16 times 16 equals but its Square root would just be 16 ._.
not quite let's break it into two parts: 16 and x^2 what is the square root of 16?
4
right, now what's the square root of x^2?
Thanks for the help I already firguered out the answer its B
I mean C

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