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anonymous

  • one year ago

Solve: 16x2 − 81 = 0. x = 4, 9 x = −4, −9 x = 9 over 4, x = −9 over 4 x = 81 over 16, x = −81 over 16

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  1. Vocaloid
    • one year ago
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    hint: 16x^2 - 81 = A^2 - B^2 can you tell me what A and B are?

  2. abb0t
    • one year ago
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    @pooja195 can help!

  3. anonymous
    • one year ago
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    A and B are the numbers

  4. Vocaloid
    • one year ago
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    right, but which numbers? 16x^2 - 81 = A^2 - B^2 what is A = ?

  5. anonymous
    • one year ago
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    - 9 over 4?

  6. Vocaloid
    • one year ago
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    ... what? |dw:1439571060249:dw|

  7. Vocaloid
    • one year ago
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    so, if A^2 = 16x^2, what is A?

  8. anonymous
    • one year ago
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    A is 16x^2

  9. Vocaloid
    • one year ago
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    nope, not quite... A^2 = 16x^2 A = ?

  10. anonymous
    • one year ago
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    A is 16^2

  11. Vocaloid
    • one year ago
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    nope, try one more time... A^2 = 16x^2 A = square root of A^2 = ?

  12. anonymous
    • one year ago
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    ITS 100

  13. anonymous
    • one year ago
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    ?

  14. Vocaloid
    • one year ago
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    what is the square root of 16x^2?

  15. anonymous
    • one year ago
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    Well 256 is what 16 times 16 equals but its Square root would just be 16 ._.

  16. Vocaloid
    • one year ago
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    not quite let's break it into two parts: 16 and x^2 what is the square root of 16?

  17. anonymous
    • one year ago
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    4

  18. Vocaloid
    • one year ago
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    right, now what's the square root of x^2?

  19. anonymous
    • one year ago
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    Thanks for the help I already firguered out the answer its B

  20. anonymous
    • one year ago
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    I mean C

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