someone help me! I have an assignment which requires me to write the equation that represents the image of an arch monument that i will post below. PLEASE HELP

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someone help me! I have an assignment which requires me to write the equation that represents the image of an arch monument that i will post below. PLEASE HELP

Mathematics
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the height of the arch is 630ft as well as the width

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this was the assignment. https://i.gyazo.com/ea2c7cf9f897771440fb99ec9074fb06.png
Start by making a sketch of it on graph paper.
do i just place the vertex at the origin?
It's probably best to place one of the ends of the foundation at the origin.
ok give me a second to sketch it
|dw:1439572894166:dw|
???
NO ONE?
That's a good start. Now, find the midpoint of the line segment containing endpoints (0,0) and (630,0)
(0, 315)
(315, 0) actually. Plot that point on your graph and draw a vertical line segment from the vertex to the midpoint of the base segment.
yea thats what i meant. and ok
That vertical line segment is essentially the axis of symmetry.
|dw:1439574756537:dw|
You should probably use the vertex form of a parabola to write the equation for it and make sure to include the correct restrictions for the domain.
|dw:1439574890871:dw|
so y = a(x-h)^2 +k ?
Yes that. You already know the values for (h,k).
what do i plug in for a though? do i leave it as it is?
You have to solve for a
To do that, insert (h,k), then for (x,y) insert (0,0)
Then solve for a
oh ok ill do that
i got a= -2/315
Show the work you did to arrive at that result
a(0-315)^2 + 630 =0 99225a + 630 = 0 99225a = -630 a = -630/99225 a = -2/315
Okay good.
So you should be able to express the equation of the parabola in vertex form. Is that all you're required to do for this problem?
Actually, that value for a is an approximation. It's not exact.
yea thats pretty much it. My teacher just told us to do that for one of the pictures given.
thanks for the help.
yw

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