## anonymous one year ago HELP PLEASEEEE =( What is a in terms of b and y? a. b+y+65 b. b-y+65 c. b+y+75 d. b-2y+45 e. b-y+75

1. nincompoop

2. anonymous

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3. nincompoop

we know that a + y = 180 we can start our exposition from here

4. anonymous

whats the next step

5. nincompoop

slow down, I am at work lol

6. anonymous

where do u work

7. nincompoop

oh right you're doing gre... ask someone else if you're in a time crunch

8. nincompoop

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9. anonymous

i dont get it

10. anonymous

ingenious @nincompoop

11. zmtgaminghd

its a

12. anonymous

I have every confidence in @nincompoop and I like the approach, of course a + y =180 (straight angle). good starting point.

13. anonymous

so what next

14. anonymous

@yomamabf what you basically have is two equations (two triangles)

15. freckles

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16. freckles

another thing you might want to use along with the equations poop pointed out is that x+y=90

17. anonymous

hi @freckles, I teach the stuff, and that isnt broken down enough for me!

18. anonymous

how do we kno that's a b inside on the other side of the b

19. freckles

@BPDlkeme234 I wasn't trying to solve it for her

20. freckles

I was pointing out useful information

21. freckles

that she could use to solve it

22. freckles

what do you mean @yomamabf

23. anonymous

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24. freckles

I use the same variable poop used called it b'

25. anonymous

Hi @ yomambf, basically what you do is start from what you know. What they are saying is, you know that the sum of the angles in a straight angle is 180 degrees (i.e. a + y)

26. freckles

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27. freckles

you can call it something other than that I just didn't want to change all the equations already pointed out

28. anonymous

i usually really like geometry but im confused

29. anonymous

Are you listening a + y = 180 degrees ( a straight angle [ i.e. angle of 180 degrees])

30. anonymous

okay and?

31. freckles

|dw:1439576026035:dw| you were given these equations: $b'=180-(x+10)-(y+5) \\ b'=180-x-10-y-5 \\ b'=(180-10-5)-(x+y) \\ \text{ recall we also have } x+y=90$

32. freckles

can you find b'?

33. anonymous

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34. anonymous

we are saying b degrees plus b' (the angle inside the triangle next to b is also 180 degrees ( a straight angle)

35. anonymous

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36. anonymous

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37. anonymous

@nimcompoop and @freckles described it as b = 180 - b' (@freckles using original equations by @nimcompoop)

38. anonymous

got it nvm this was super easy i followed the rule that |dw:1439576326648:dw|

39. anonymous

exterior angle equal to the sum of the two interior opposite angles

40. anonymous

what was the method u guys were talking about

41. anonymous

All that @freckles said was if b + b' = 180 and the sum of all the angles in the triangle equals 180 degrees then b' + (x + 10) + (y+5) must equal 180 degrees

42. anonymous

yea i got that what's next

43. anonymous

what about the other triangle, did you get that?

44. anonymous

yea its a = 90+x

45. freckles

this is where I was going: |dw:1439576736012:dw| $b'=180-(x+10)-(y+5) \\ b'=180-x-10-y-5 \\ b'=(180-10-5)-(x+y) \\ \text{ recall we also have } x+y=90$ $b'=165-90 \\ b'=75 \\ \text{ now realize } \\ y+a=b+b' \\ y+a=b+75 \\ \text{ then solve for } a \\ a=b-y+75$

46. anonymous

whered the 165 come from

47. anonymous

so, firstly expres b in tems of x and y

48. freckles

180-10-5

49. anonymous

got it thanks

50. anonymous

Well done @freckles!

51. nincompoop

The simplest exposition (minus all the details), would be a+y = 180 b + b' = 180 so a+y = b+b' we want to solve for a, then it follows a = b+b' -y the rest of the details can be plugged in from the information of the other triangle containing b'

52. nincompoop

haha I didn't even notice that the other triangle was a right-triangle I am not sure if there is such a rule |dw:1439579564602:dw|

53. anonymous

there is

54. nincompoop

whatever rule it is, can be figured out without any prior knowledge of it.