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anonymous

  • one year ago

HELP PLEASEEEE =( What is a in terms of b and y? a. b+y+65 b. b-y+65 c. b+y+75 d. b-2y+45 e. b-y+75

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  1. nincompoop
    • one year ago
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    where is your original equation?

  2. anonymous
    • one year ago
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    |dw:1439572787323:dw|

  3. nincompoop
    • one year ago
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    we know that a + y = 180 we can start our exposition from here

  4. anonymous
    • one year ago
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    whats the next step

  5. nincompoop
    • one year ago
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    slow down, I am at work lol

  6. anonymous
    • one year ago
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    where do u work

  7. nincompoop
    • one year ago
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    oh right you're doing gre... ask someone else if you're in a time crunch

  8. nincompoop
    • one year ago
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    |dw:1439574194246:dw|

  9. anonymous
    • one year ago
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    i dont get it

  10. anonymous
    • one year ago
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    ingenious @nincompoop

  11. zmtgaminghd
    • one year ago
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    its a

  12. anonymous
    • one year ago
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    I have every confidence in @nincompoop and I like the approach, of course a + y =180 (straight angle). good starting point.

  13. anonymous
    • one year ago
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    so what next

  14. anonymous
    • one year ago
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    @yomamabf what you basically have is two equations (two triangles)

  15. freckles
    • one year ago
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    |dw:1439575651614:dw|

  16. freckles
    • one year ago
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    another thing you might want to use along with the equations poop pointed out is that x+y=90

  17. anonymous
    • one year ago
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    hi @freckles, I teach the stuff, and that isnt broken down enough for me!

  18. anonymous
    • one year ago
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    how do we kno that's a b inside on the other side of the b

  19. freckles
    • one year ago
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    @BPDlkeme234 I wasn't trying to solve it for her

  20. freckles
    • one year ago
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    I was pointing out useful information

  21. freckles
    • one year ago
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    that she could use to solve it

  22. freckles
    • one year ago
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    what do you mean @yomamabf

  23. anonymous
    • one year ago
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    |dw:1439575867408:dw|

  24. freckles
    • one year ago
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    I use the same variable poop used called it b'

  25. anonymous
    • one year ago
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    Hi @ yomambf, basically what you do is start from what you know. What they are saying is, you know that the sum of the angles in a straight angle is 180 degrees (i.e. a + y)

  26. freckles
    • one year ago
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    |dw:1439575943969:dw|

  27. freckles
    • one year ago
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    you can call it something other than that I just didn't want to change all the equations already pointed out

  28. anonymous
    • one year ago
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    i usually really like geometry but im confused

  29. anonymous
    • one year ago
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    Are you listening a + y = 180 degrees ( a straight angle [ i.e. angle of 180 degrees])

  30. anonymous
    • one year ago
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    okay and?

  31. freckles
    • one year ago
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    |dw:1439576026035:dw| you were given these equations: \[b'=180-(x+10)-(y+5) \\ b'=180-x-10-y-5 \\ b'=(180-10-5)-(x+y) \\ \text{ recall we also have } x+y=90\]

  32. freckles
    • one year ago
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    can you find b'?

  33. anonymous
    • one year ago
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    |dw:1439576122047:dw|

  34. anonymous
    • one year ago
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    we are saying b degrees plus b' (the angle inside the triangle next to b is also 180 degrees ( a straight angle)

  35. anonymous
    • one year ago
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    |dw:1439576211471:dw|

  36. anonymous
    • one year ago
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    |dw:1439576256448:dw|

  37. anonymous
    • one year ago
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    @nimcompoop and @freckles described it as b = 180 - b' (@freckles using original equations by @nimcompoop)

  38. anonymous
    • one year ago
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    got it nvm this was super easy i followed the rule that |dw:1439576326648:dw|

  39. anonymous
    • one year ago
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    exterior angle equal to the sum of the two interior opposite angles

  40. anonymous
    • one year ago
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    what was the method u guys were talking about

  41. anonymous
    • one year ago
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    All that @freckles said was if b + b' = 180 and the sum of all the angles in the triangle equals 180 degrees then b' + (x + 10) + (y+5) must equal 180 degrees

  42. anonymous
    • one year ago
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    yea i got that what's next

  43. anonymous
    • one year ago
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    what about the other triangle, did you get that?

  44. anonymous
    • one year ago
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    yea its a = 90+x

  45. freckles
    • one year ago
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    this is where I was going: |dw:1439576736012:dw| \[b'=180-(x+10)-(y+5) \\ b'=180-x-10-y-5 \\ b'=(180-10-5)-(x+y) \\ \text{ recall we also have } x+y=90\] \[b'=165-90 \\ b'=75 \\ \text{ now realize } \\ y+a=b+b' \\ y+a=b+75 \\ \text{ then solve for } a \\ a=b-y+75\]

  46. anonymous
    • one year ago
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    whered the 165 come from

  47. anonymous
    • one year ago
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    so, firstly expres b in tems of x and y

  48. freckles
    • one year ago
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    180-10-5

  49. anonymous
    • one year ago
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    got it thanks

  50. anonymous
    • one year ago
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    Well done @freckles!

  51. nincompoop
    • one year ago
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    The simplest exposition (minus all the details), would be a+y = 180 b + b' = 180 so a+y = b+b' we want to solve for a, then it follows a = b+b' -y the rest of the details can be plugged in from the information of the other triangle containing b'

  52. nincompoop
    • one year ago
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    haha I didn't even notice that the other triangle was a right-triangle I am not sure if there is such a rule |dw:1439579564602:dw|

  53. anonymous
    • one year ago
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    there is

  54. nincompoop
    • one year ago
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    whatever rule it is, can be figured out without any prior knowledge of it.

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