anonymous
  • anonymous
solve the system by either elimination or substitution 3x-5y=21 2x+y=1 A.2,-3 B.2,3 C.-2,-1 D.-2,1 My guess is c
Mathematics
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anonymous
  • anonymous
solve the system by either elimination or substitution 3x-5y=21 2x+y=1 A.2,-3 B.2,3 C.-2,-1 D.-2,1 My guess is c
Mathematics
katieb
  • katieb
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freckles
  • freckles
you could multiply the second equation by 5 and then add the equations together afterwards thus eliminating the y
freckles
  • freckles
what would the second equation look like after multiplying it by 5?
freckles
  • freckles
\[2x+y=1 \\ 5(2x+y)=5(1) \\ \text{ use distributive property on the left } \\ 5(2x+y)=5\]

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freckles
  • freckles
remember that is a(b+c)=ab+ac this is distributive property
anonymous
  • anonymous
i got 10x+5y=5
freckles
  • freckles
|dw:1439573529408:dw| ok add the equations now
freckles
  • freckles
|dw:1439573561932:dw|
freckles
  • freckles
can you evaluate the following: 3+10 -5+5 and 21+5
anonymous
  • anonymous
for the first one i got 13x=26
freckles
  • freckles
|dw:1439573634678:dw|
freckles
  • freckles
and 26/13 equals?
anonymous
  • anonymous
2
freckles
  • freckles
going back to either equation we started with we will now insert this x to find y I choose that second equation that was: 2x+y=1 2(2)+y=1 4+y=1 solve for y
anonymous
  • anonymous
-3
freckles
  • freckles
|dw:1439573810726:dw|
freckles
  • freckles
yep and as you see it doesn't matter which equation you used to find the other number
anonymous
  • anonymous
Thank you very much! can you help me with one more
freckles
  • freckles
sure i might be able to post a new question just in case

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