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anonymous

  • one year ago

solve the system by either elimination or substitution 3x-5y=21 2x+y=1 A.2,-3 B.2,3 C.-2,-1 D.-2,1 My guess is c

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  1. freckles
    • one year ago
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    you could multiply the second equation by 5 and then add the equations together afterwards thus eliminating the y

  2. freckles
    • one year ago
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    what would the second equation look like after multiplying it by 5?

  3. freckles
    • one year ago
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    \[2x+y=1 \\ 5(2x+y)=5(1) \\ \text{ use distributive property on the left } \\ 5(2x+y)=5\]

  4. freckles
    • one year ago
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    remember that is a(b+c)=ab+ac this is distributive property

  5. anonymous
    • one year ago
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    i got 10x+5y=5

  6. freckles
    • one year ago
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    |dw:1439573529408:dw| ok add the equations now

  7. freckles
    • one year ago
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    |dw:1439573561932:dw|

  8. freckles
    • one year ago
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    can you evaluate the following: 3+10 -5+5 and 21+5

  9. anonymous
    • one year ago
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    for the first one i got 13x=26

  10. freckles
    • one year ago
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    |dw:1439573634678:dw|

  11. freckles
    • one year ago
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    and 26/13 equals?

  12. anonymous
    • one year ago
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    2

  13. freckles
    • one year ago
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    going back to either equation we started with we will now insert this x to find y I choose that second equation that was: 2x+y=1 2(2)+y=1 4+y=1 solve for y

  14. anonymous
    • one year ago
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    -3

  15. freckles
    • one year ago
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    |dw:1439573810726:dw|

  16. freckles
    • one year ago
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    yep and as you see it doesn't matter which equation you used to find the other number

  17. anonymous
    • one year ago
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    Thank you very much! can you help me with one more

  18. freckles
    • one year ago
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    sure i might be able to post a new question just in case

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