anonymous
  • anonymous
please help will fan and medal. http://assets.openstudy.com/updates/attachments/55ce201ae4b0016bb016cf55-enchanted_bubbles-1439572007964-screenshot_1.png
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
welshfella
  • welshfella
there are 3 zeros:- -1 duplicity 2 and 1 so in factor form it is (x+1)^2(x-1)

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anonymous
  • anonymous
I am confused.
welshfella
  • welshfella
if you look at the graph you see that at x = -1 the graph touches the x-axis and the it pass through the point where x = 1 these are called the zeros of the function its a cubic function so it has 3 zeros;- 2 at x = -1 and 1 at x = 1 if we write (x + 1)^2(x - 1) = 0 we get x -1 = 0 or (x +1)^2 = 0 giving x = 1 and x = -1 (twice)
welshfella
  • welshfella
so iy you expand (x - 1)(x + 1)(x + 1) you'll get the correct function
welshfella
  • welshfella
do it by multiplying the last 2 factors first - giving x^2 + 2x + 1 so we have (x - 1)(x^2 + 2x+ 1) = ?
anonymous
  • anonymous
\[x^3+x^2−x−1=?\]
welshfella
  • welshfella
yep
anonymous
  • anonymous
Thank you!
welshfella
  • welshfella
welcome

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