A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

nuccioreggie

  • one year ago

help

  • This Question is Closed
  1. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Jack uses a probability simulator to roll a six-sided number cube 100 times and to flip a coin 100 times. The results of the experiment are shown below: Number on the Cube Number of Times Rolled 1 16 2 14 3 5 4 17 5 21 6 27 Heads Tails 41 59 Using Jack's simulation, what is the probability of rolling a 6 on the number cube and the coin landing on heads? fraction 1,107 over 10,000 fraction 1,593 over 10,000 fraction 27 over 100 fraction 41 over 100

  2. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Michele_Laino

  3. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    here we have two independent events, namely the flipping of a coin and the rolling of a six-sided cube. The probability to get a six, is: p1=favorable outcomes / possible outcomes= =27/(16+14+5+17+21+27)=...? the probability to get a head is: p2=favorable outcomes/ possible outcomes= 41/(41+59)=...?

  4. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    60

  5. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what is 60?

  6. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    please you have to compute p1 and p2

  7. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    95.6875

  8. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\Large \begin{gathered} {p_1} = \frac{{27}}{{16 + 14 + 5 + 17 + 21 + 27}} = ...? \hfill \\ \hfill \\ {p_2} = \frac{{41}}{{41 + 59}} = ...? \hfill \\ \end{gathered} \]

  9. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so D

  10. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm sorry, option D is incorrect!

  11. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wait sorry its c

  12. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    please check my computation: \[\Large \begin{gathered} {p_1} = \frac{{27}}{{16 + 14 + 5 + 17 + 21 + 27}} = \frac{{27}}{{100}} \hfill \\ \hfill \\ {p_2} = \frac{{41}}{{41 + 59}} = \frac{{41}}{{100}} \hfill \\ \end{gathered} \] am I right?

  13. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes so its C

  14. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    now, since those two ebents are independent events, then the requested probability is given by the subsequent product: \[\Large {p_1} \cdot {p_2} = \frac{{27}}{{100}} \cdot \frac{{41}}{{100}} = ...?\]

  15. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    events*

  16. nuccioreggie
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    A

  17. Michele_Laino
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that's right!

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.