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anonymous
 one year ago
can anyone help me please!!!
anonymous
 one year ago
can anyone help me please!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help with 1  7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02.Carter=f(x)=10∗(2)^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what about 37?? @ms.hi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04.Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x On 3rd day : Amber=f(3)=3∗(4)^3 = 192 Ben=f(x)=2∗(3)^3 = 54 Carter=f(x)=10∗(2)^3 = 80 On 10th day : Amber=f(10)=3∗(4)^10 = 3145728 Ben=f(10)=2∗(3)^10 = 118098 Carter=f(10)=10∗(2)^10 = 10240 Amber's shares are increasing by 4 times each day where as Carter's shares are only increasing by 2 times each day. So Amber's shares are expected to be more on day 10 compared to Carter's

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05.This graph compares to the original graph of Amber’s photo share is both of them are exponential growths. The new function goes 45 units up from the original function which was f(x)=3(4)^x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06.Notice that Amber has started with just 3 shares and Carter started with 10 shares. Still Carter's shares are very low compared to Amber on day 10. Amber's shares are increasing by 4 times each day where as Carter's shares are only increasing by 2 times each day. So Amber's shares are expected to be more on day 10 compared to Carter's

pooja195
 one year ago
Best ResponseYou've already chosen the best response.0Are these questions from a test?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no for a project @pooja195

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you @ms.hi but do you know how to graph because i'm not that good at it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats ok thank you any ways:) @ms.hi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0https://www.desmos.com/calculator/3t1miijac8 heres the graph
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