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anonymous
 one year ago
system of equation
y=x^2+3
y=x+5
anonymous
 one year ago
system of equation y=x^2+3 y=x+5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if anyone could show me the steps?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We generally use one to solve the other. Start with simplest. y = x + 5 y(5) = x+ 5 (5) y 5 = x therefore substituting in eq .1 we get: y = (y5)^2 +3 y = (y^2 10y +25) + 3 y = y^2 10y + 22 subtract y from both sides to get: 0 = y^2 9y + 22 solve to get: dw:1439459437832:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439459686316:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so @BPDlkeme234 so the answer is 9 +or 72over 22

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1y = (y5)^2 +3 y = (y^2 10y +25) + 3 this should actually come to y^210yy+25+3=0 y^211y+28=0 can you finish solving for y y^211y+28 is factorable

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@myininaya how would I factor y^2

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1why would you want to factor y^2?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1y^2 is already in factored form... I was wanting you to factor y^211y+28

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1what two numbers multiply to be 28 and add up to be 11?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y7 and y4 @myininaya

myininaya
 one year ago
Best ResponseYou've already chosen the best response.17(4)=28 74=11 so y^211y+28=(y7)(y4)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1so you can solve (y7)(y4)=0 by solving both y7=0 or y4=0

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1once you find the y's then plug each y into: \[x=y5\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I still do not understand why im sorry im vary lost @myininaya

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1understand what exactly?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1if you don't understand how to factor you can use the quadratic formula since it is a quadratic equation

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[ax^2+bx+c=0 \\ \implies x=\frac{b \pm \sqrt{b^24ac}}{2a}\]

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1\[y^211y+28=0 \\ \implies y=\frac{(11) \pm \sqrt{(11)^24(1)(28)}}{2(1)}\] do you understand how to simplify this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how to find the answer I thought he answer was y7 and x4

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1before we can find the ordered pairs we have to find the y values do you know how to solve the equation y^211y+28=0?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1when you say things like y7 does that mean y=7?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1if so when you said "y7 and y4 " which actually in your case means y=7 or y=4 then that is right for the y's... now you had x=y5 now if y=7 then x=75=? and if y=4 then x=45=? so the ordered pairs are (75,7) (45,4)

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1just need to simplify the xcoordinates for each point
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