anonymous
  • anonymous
A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used = 43.2 mL concentration NaOH = 0.15 M mL H2SO4 = 20.5 mL Notice that H2SO4 releases 2 H+ per mole. What is the concentration of H2SO4? a) 0.036 M b) 0.16 M c) 0.63 M d) 6.3 M
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Cuanchi
  • Cuanchi
1) you have to write down and balance the neutralization equation 2) calculate how many moles of NaOH you have in 43.2 mL 0.15 M. moles= Molarity x Volume (L) 3) according to the soichiometry of the reaction calculate how many moles of H2SO4 you need 4) calculate the molarity of H2SO4 (Molarity = moles/ volume in L) moles is the value that you calculate in 3) and volume you have to convert the 20.5 mL to L
anonymous
  • anonymous
ok. thank you.
Cuanchi
  • Cuanchi
did you got the answer?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
no. I got the answer wrong. I thought it was 0.63 M. but that was incorrect.
Rushwr
  • Rushwr
do u still need the answer?
Rushwr
  • Rushwr
I think U might have got the equation wrong ! So the balanced equation for the titration would be :\[2NaOH + H _{2}SO _{4} \rightarrow Na _{2}SO _{4} + 2H _{2}O\]
Rushwr
  • Rushwr
Now you find the no. of moles of NaOH as they have given us the volume and the concentrations ! Use \[C = \frac{ n }{ V }\]
Rushwr
  • Rushwr
remember no of moles of NaOH is twice the number of H2SO4 ( Look at the equation) What I go for this was \[0.15 * 43.2 * 10^{-3} = 6.48 * 10^{-3}\] So now divide the no of moles of NaOH by 2 to find out the no. of moles of H2SO4 That would be 3.24 * 10 ^-3 Now again use C=n/v for H2SO4 and obtain the concentration . Always remember to convert ml to liters. So finally I obtained 0.158 which is approximately equals to 0.16 the 2nd answer !

Looking for something else?

Not the answer you are looking for? Search for more explanations.