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anonymous
 one year ago
A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected:
mL of NaOH used = 43.2 mL
concentration NaOH = 0.15 M
mL H2SO4 = 20.5 mL
Notice that H2SO4 releases 2 H+ per mole.
What is the concentration of H2SO4?
a) 0.036 M
b) 0.16 M
c) 0.63 M
d) 6.3 M
anonymous
 one year ago
A titration was performed in a lab situation. H2SO4 was titrated with NaOH. The following data was collected: mL of NaOH used = 43.2 mL concentration NaOH = 0.15 M mL H2SO4 = 20.5 mL Notice that H2SO4 releases 2 H+ per mole. What is the concentration of H2SO4? a) 0.036 M b) 0.16 M c) 0.63 M d) 6.3 M

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01) you have to write down and balance the neutralization equation 2) calculate how many moles of NaOH you have in 43.2 mL 0.15 M. moles= Molarity x Volume (L) 3) according to the soichiometry of the reaction calculate how many moles of H2SO4 you need 4) calculate the molarity of H2SO4 (Molarity = moles/ volume in L) moles is the value that you calculate in 3) and volume you have to convert the 20.5 mL to L

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you got the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no. I got the answer wrong. I thought it was 0.63 M. but that was incorrect.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0do u still need the answer?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0I think U might have got the equation wrong ! So the balanced equation for the titration would be :\[2NaOH + H _{2}SO _{4} \rightarrow Na _{2}SO _{4} + 2H _{2}O\]

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0Now you find the no. of moles of NaOH as they have given us the volume and the concentrations ! Use \[C = \frac{ n }{ V }\]

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.0remember no of moles of NaOH is twice the number of H2SO4 ( Look at the equation) What I go for this was \[0.15 * 43.2 * 10^{3} = 6.48 * 10^{3}\] So now divide the no of moles of NaOH by 2 to find out the no. of moles of H2SO4 That would be 3.24 * 10 ^3 Now again use C=n/v for H2SO4 and obtain the concentration . Always remember to convert ml to liters. So finally I obtained 0.158 which is approximately equals to 0.16 the 2nd answer !
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