anonymous
  • anonymous
here
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
jtvatsim
  • jtvatsim
5(a) doesn't look too bad. You could assume without loss of generality that y > z, that is, y = z + r for some r > 0, and show that the given expression yields y for max(y,z) and z for min(y,z).

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jtvatsim
  • jtvatsim
5(b) should follow quickly from 5(a)... but I haven't looked at it in depth.
anonymous
  • anonymous
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anonymous
  • anonymous
anonymous
  • anonymous
thats my book
jtvatsim
  • jtvatsim
OK, thanks.
jtvatsim
  • jtvatsim
I should definitely be able to get a proof for 4. There is one in my book that I can probably use.
anonymous
  • anonymous
ok
anonymous
  • anonymous
what about 3?
jtvatsim
  • jtvatsim
Haven't quite figured out what they are talking about yet... but I'm not giving up yet. :)
anonymous
  • anonymous
ok. thanks
jtvatsim
  • jtvatsim
Here is my attempted proof for problem 4. I'm mentally tired right now, so I'll take a look at problem 3 later. Hope this first proof helps! :)

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