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anonymous
 one year ago
here
anonymous
 one year ago
here

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jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.15(a) doesn't look too bad. You could assume without loss of generality that y > z, that is, y = z + r for some r > 0, and show that the given expression yields y for max(y,z) and z for min(y,z).

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.15(b) should follow quickly from 5(a)... but I haven't looked at it in depth.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1I should definitely be able to get a proof for 4. There is one in my book that I can probably use.

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Haven't quite figured out what they are talking about yet... but I'm not giving up yet. :)

jtvatsim
 one year ago
Best ResponseYou've already chosen the best response.1Here is my attempted proof for problem 4. I'm mentally tired right now, so I'll take a look at problem 3 later. Hope this first proof helps! :)
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