1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas:
PbS + O2 PbO + SO2
Balance the equation and describe in words the electron transfer(s) that takes place.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Do you know how to balance it?
Ok so the only one that is currently unbalanced is the oxygen there is two on the left and three on the right side
If we add a two in front of the PbO
PbS + O2 --> 2PbO + SO2
Now Pb is unbalanced as well to balance I'll put a 2 in front of the PbS
2PbS + O2 --> 2PbO + SO2
Pb is balanced but S isn't anymore so we will put a 2 in front of the SO2
2PbS + O2 --> 2PbO + 2SO2
Now Pb is balanced and S is balanced only O is unbalanced
We have 2 on the left and 6 on the right
To balance we need 6 oxygen on the left
2PbS + 3O2 --> 2PbO + 2SO2
That is the balanced equation