1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas: PbS + O2  PbO + SO2 Balance the equation and describe in words the electron transfer(s) that takes place.

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1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas: PbS + O2  PbO + SO2 Balance the equation and describe in words the electron transfer(s) that takes place.

Chemistry
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Do you know how to balance it?
no
Ok so the only one that is currently unbalanced is the oxygen there is two on the left and three on the right side If we add a two in front of the PbO PbS + O2 --> 2PbO + SO2 Now Pb is unbalanced as well to balance I'll put a 2 in front of the PbS 2PbS + O2 --> 2PbO + SO2 Pb is balanced but S isn't anymore so we will put a 2 in front of the SO2 2PbS + O2 --> 2PbO + 2SO2 Now Pb is balanced and S is balanced only O is unbalanced We have 2 on the left and 6 on the right To balance we need 6 oxygen on the left 6/2=3 2PbS + 3O2 --> 2PbO + 2SO2 That is the balanced equation

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