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anonymous

  • one year ago

1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas: PbS + O2  PbO + SO2 Balance the equation and describe in words the electron transfer(s) that takes place.

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  1. taramgrant0543664
    • one year ago
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    Do you know how to balance it?

  2. anonymous
    • one year ago
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    no

  3. taramgrant0543664
    • one year ago
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    Ok so the only one that is currently unbalanced is the oxygen there is two on the left and three on the right side If we add a two in front of the PbO PbS + O2 --> 2PbO + SO2 Now Pb is unbalanced as well to balance I'll put a 2 in front of the PbS 2PbS + O2 --> 2PbO + SO2 Pb is balanced but S isn't anymore so we will put a 2 in front of the SO2 2PbS + O2 --> 2PbO + 2SO2 Now Pb is balanced and S is balanced only O is unbalanced We have 2 on the left and 6 on the right To balance we need 6 oxygen on the left 6/2=3 2PbS + 3O2 --> 2PbO + 2SO2 That is the balanced equation

  4. anonymous
    • one year ago
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    okay

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