A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas:
PbS + O2 PbO + SO2
Balance the equation and describe in words the electron transfer(s) that takes place.
anonymous
 one year ago
1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas: PbS + O2 PbO + SO2 Balance the equation and describe in words the electron transfer(s) that takes place.

This Question is Closed

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to balance it?

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0Ok so the only one that is currently unbalanced is the oxygen there is two on the left and three on the right side If we add a two in front of the PbO PbS + O2 > 2PbO + SO2 Now Pb is unbalanced as well to balance I'll put a 2 in front of the PbS 2PbS + O2 > 2PbO + SO2 Pb is balanced but S isn't anymore so we will put a 2 in front of the SO2 2PbS + O2 > 2PbO + 2SO2 Now Pb is balanced and S is balanced only O is unbalanced We have 2 on the left and 6 on the right To balance we need 6 oxygen on the left 6/2=3 2PbS + 3O2 > 2PbO + 2SO2 That is the balanced equation
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.