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anonymous

  • one year ago

is x=6 extranous or no

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  1. anonymous
    • one year ago
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    @taramgrant0543664

  2. xapproachesinfinity
    • one year ago
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    where is the equation?

  3. xapproachesinfinity
    • one year ago
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    you want me to make one lol

  4. anonymous
    • one year ago
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  5. xapproachesinfinity
    • one year ago
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    ok good!! what did you do thus far?

  6. anonymous
    • one year ago
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    igt x=6

  7. anonymous
    • one year ago
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    but ineed to know if its extranous or not

  8. xapproachesinfinity
    • one year ago
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    well put it back into the equation and see if it does work? if we put six what is the problem?

  9. xapproachesinfinity
    • one year ago
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    It does not really work does it?

  10. xapproachesinfinity
    • one year ago
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    that will produce division by zero yes? which is not allowed

  11. xapproachesinfinity
    • one year ago
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    you agree or disagree? what is your stance?

  12. xapproachesinfinity
    • one year ago
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    hhhh well can we divide by 0 can we have 6/0 in the left in the right 6/0-6/2

  13. xapproachesinfinity
    • one year ago
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    what is 6/0? can you have an answer?

  14. anonymous
    • one year ago
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    not so not extanrous

  15. xapproachesinfinity
    • one year ago
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    ok once step at a time what is extraneous solution

  16. xapproachesinfinity
    • one year ago
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    let me answer this, it is a solution that you find by correct algebraic maneuvers but it does not work for the equation when we put it back

  17. anonymous
    • one year ago
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    An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

  18. xapproachesinfinity
    • one year ago
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    yeah that's the definition right there so from the start x=6 is excluded from domain yes

  19. xapproachesinfinity
    • one year ago
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    but when you were solving the equation to transform it using some maneuvers then you got x=6

  20. xapproachesinfinity
    • one year ago
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    that's why we say it is extraneous solution because it is not included in the domain

  21. xapproachesinfinity
    • one year ago
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    here is what we do \[\frac{x}{x-6}=\frac{x}{x-6}-\frac{6}{2}\] domain here is every real number except 6

  22. xapproachesinfinity
    • one year ago
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    slight mistake first should be 6/x-6

  23. xapproachesinfinity
    • one year ago
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    so \[\frac{6}{x-6}=\frac{x}{x-6}-\frac{6}{2}\] \[\frac{6}{x-6}=\frac{2x-6}{2(x-6)}\] \[\frac{6}{\cancel {x-6}}=\frac{2x-6}{2\cancel{(x-6)}}\] \[6=\frac{2x-6}{2}\Longrightarrow 12 =2x-6 \Longrightarrow x=9\]

  24. xapproachesinfinity
    • one year ago
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    how did you got x=6?

  25. xapproachesinfinity
    • one year ago
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    i got 9

  26. xapproachesinfinity
    • one year ago
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    oh my bad i miss something

  27. xapproachesinfinity
    • one year ago
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    correct the solution found is x=6 just missed up above in line 2

  28. xapproachesinfinity
    • one year ago
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    so 6 we said excluded therefore it is extraneous

  29. xapproachesinfinity
    • one year ago
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    was that helpful? clear?

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