is x=6 extranous or no

- anonymous

is x=6 extranous or no

- jamiebookeater

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- anonymous

- xapproachesinfinity

where is the equation?

- xapproachesinfinity

you want me to make one lol

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## More answers

- anonymous

##### 1 Attachment

- xapproachesinfinity

ok good!!
what did you do thus far?

- anonymous

igt x=6

- anonymous

but ineed to know if its extranous or not

- xapproachesinfinity

well put it back into the equation and see if it does work?
if we put six what is the problem?

- xapproachesinfinity

It does not really work does it?

- xapproachesinfinity

that will produce division by zero yes?
which is not allowed

- xapproachesinfinity

you agree or disagree? what is your stance?

- xapproachesinfinity

hhhh well can we divide by 0
can we have 6/0 in the left
in the right 6/0-6/2

- xapproachesinfinity

what is 6/0? can you have an answer?

- anonymous

not so not extanrous

- xapproachesinfinity

ok once step at a time
what is extraneous solution

- xapproachesinfinity

let me answer this,
it is a solution that you find by correct algebraic maneuvers but it does not work for the equation when we put it back

- anonymous

An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

- xapproachesinfinity

yeah that's the definition right there
so from the start x=6 is excluded from domain yes

- xapproachesinfinity

but when you were solving the equation to transform it using some maneuvers then you got x=6

- xapproachesinfinity

that's why we say it is extraneous solution because it is not included in the domain

- xapproachesinfinity

here is what we do \[\frac{x}{x-6}=\frac{x}{x-6}-\frac{6}{2}\]
domain here is every real number except 6

- xapproachesinfinity

slight mistake first should be 6/x-6

- xapproachesinfinity

so \[\frac{6}{x-6}=\frac{x}{x-6}-\frac{6}{2}\]
\[\frac{6}{x-6}=\frac{2x-6}{2(x-6)}\]
\[\frac{6}{\cancel {x-6}}=\frac{2x-6}{2\cancel{(x-6)}}\]
\[6=\frac{2x-6}{2}\Longrightarrow 12 =2x-6 \Longrightarrow x=9\]

- xapproachesinfinity

how did you got x=6?

- xapproachesinfinity

i got 9

- xapproachesinfinity

oh my bad i miss something

- xapproachesinfinity

correct the solution found is x=6
just missed up above in line 2

- xapproachesinfinity

so 6 we said excluded therefore it is extraneous

- xapproachesinfinity

was that helpful? clear?

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