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AmberlyKhan

  • one year ago

Find the largest factor of 1260 which is not divisible by 6. Explain.

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  1. anonymous
    • one year ago
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    do you have a prime factorization for 1260?

  2. anonymous
    • one year ago
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    Numbers divisible by 6 are divisible by both 2 and 3, so once you have the prime factors, multiply all of them except the 2s to get the largest number not divisible by 6.

  3. anonymous
    • one year ago
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    \[1260=2^2 *3^2* 5 *7\]

  4. anonymous
    • one year ago
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    315

  5. anonymous
    • one year ago
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    3^2∗5∗7

  6. AmberlyKhan
    • one year ago
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    Thanks! @peachpi and @robtobey. But why would I multiply the 3s if you stated that 6 is divisible by 2 and 3? Kinda confused about why you canceled out the 2s to get the answer.

  7. Loser66
    • one year ago
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    Because 2 and 3 cannot be at the expression at the same time. If they exist at the same time, then the number will be divisible by 6

  8. AmberlyKhan
    • one year ago
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    So why cancel out 2 but not 3? If only one can be present, cant it be 3 also? @Loser66

  9. Loser66
    • one year ago
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    Because when you cancel 3, the number is not divisible by 6 but it is NOT the largest one.

  10. Loser66
    • one year ago
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    \(3^2*5*7 = 325 > 2^2*5*7 = 140\)

  11. AmberlyKhan
    • one year ago
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    Ohhhhhh..... Thanks! I FINALLY get it. :) @Loser66

  12. Loser66
    • one year ago
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    np

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