AmberlyKhan
  • AmberlyKhan
Find the largest factor of 1260 which is not divisible by 6. Explain.
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
do you have a prime factorization for 1260?
anonymous
  • anonymous
Numbers divisible by 6 are divisible by both 2 and 3, so once you have the prime factors, multiply all of them except the 2s to get the largest number not divisible by 6.
anonymous
  • anonymous
\[1260=2^2 *3^2* 5 *7\]

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anonymous
  • anonymous
315
anonymous
  • anonymous
3^2∗5∗7
AmberlyKhan
  • AmberlyKhan
Thanks! @peachpi and @robtobey. But why would I multiply the 3s if you stated that 6 is divisible by 2 and 3? Kinda confused about why you canceled out the 2s to get the answer.
Loser66
  • Loser66
Because 2 and 3 cannot be at the expression at the same time. If they exist at the same time, then the number will be divisible by 6
AmberlyKhan
  • AmberlyKhan
So why cancel out 2 but not 3? If only one can be present, cant it be 3 also? @Loser66
Loser66
  • Loser66
Because when you cancel 3, the number is not divisible by 6 but it is NOT the largest one.
Loser66
  • Loser66
\(3^2*5*7 = 325 > 2^2*5*7 = 140\)
AmberlyKhan
  • AmberlyKhan
Ohhhhhh..... Thanks! I FINALLY get it. :) @Loser66
Loser66
  • Loser66
np

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