anonymous
  • anonymous
Write the equation of a hyperbola with vertices at (-7, 0) and (7, 0) and co-vertices (0, -4) and (0, 4).
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
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anonymous
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anonymous
  • anonymous

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anonymous
  • anonymous
anonymous
  • anonymous
I think the first answer choice is correct because the vertices (major axis) are on the x-axis and the co-vertices (minor axis) are on the y-axis. And the major axis is always the one that's positive in hyperbolas; so 7^2=49 goes under x^2 and 4^2=16 goes under -y^2 x^2 _ y^2 --- --- 49 16
anonymous
  • anonymous
Does that make any sense? Because I can explain it a little more.
anonymous
  • anonymous
correct center Is (0,0) a=7 b=4 eq. of hyperbola is \[\frac{ x^2 }{ a^2 }-\frac{ y^2 }{ b^2 }=1\]

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