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yeval76
 one year ago
Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠OPQ?
yeval76
 one year ago
Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠OPQ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember that if a quadrilateral is inscribed in a circle, the opposite angles sum up 180 degrees

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, if you sum ROP + PQR = 180

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ROP=x+16 and PQR=6x4, so ROP+PQR=x+16+6x4=180

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x+16+6x4 = 7x+12 = 180, can you do this?

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0I got 12=12=180 @Natriumhydrid

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Quadrilaterals add up to 360, so couldn't you add all of the equations (angle p=x) and set them equal to 360

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x+16) + (2x+16) + (6x4) + x =360 angle P=x

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0I know that the opposite angles in a inscribed quadrilateral are supplementary.

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0So x=83 @Katherine2016

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Do we apply that x to all the equations around the circle? @Katherine2016

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you get 12=12=180?

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Omg I didn't put the answer choices: m∠OPQ + (2x + 16)° = 180° m∠OPQ = (6x − 4)° + (2x + 16)° m∠OPQ + (x + 16)° + (6x − 4)°= 360° m∠OPQ = (x + 16)° + (6x − 4)°

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0I think its the first one?

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Because, since the opposite angles are supplementary, they would equal 180 so angle OPQ plus its opposite angle which is (2x+16) would be 180...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.07x+12 = 180 7x = 168 x=24, so the x in the image is 24, replacing in ∠ORQ we get ∠ORQ=64, so ∠OPQ must be supplementary then ∠OPQ=116

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with another question? @Natriumhydrid

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: What is the measure of angle ACB?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK, so, if angle ABX=42, then the arc AX=84 (because is inscribed angle), and the arc AB=100, now using the formula of external angle, angle ACB=(10084)/2=16/2=8, so ACB=8degrees

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Omg again! I forgot to put the answer choices! 29° 8° 16° 21°

yeval76
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! @Natriumhydrid
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