anonymous
  • anonymous
(cos Θ + cos Θ)^2 + (cos Θ + cos Θ)^2 answers are sin2 Θ 4 8 cos2 Θ
Mathematics
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anonymous
  • anonymous
(cos Θ + cos Θ)^2 + (cos Θ + cos Θ)^2 answers are sin2 Θ 4 8 cos2 Θ
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
SOMEONE PLEASE HELP
Astrophysics
  • Astrophysics
I just showed you this :\
Astrophysics
  • Astrophysics
Someone else isn't going to get a different answer...they will tell you your options are wrong as well, we got \[8 \cos^2(\theta)\]

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anonymous
  • anonymous
yes but i was hoping someone cou;d help me answer it maybe theres a different way
Astrophysics
  • Astrophysics
\[(\cos(\theta)+\cos(\theta)^2 = (2\cos \theta)^2 = 4\cos^2(\theta)\] since both sides are same we have \[4\cos^2(\theta)+4\cos^2(\theta) = 8\cos^2(\theta)\]
Astrophysics
  • Astrophysics
Your options don't make sense, either you just pick one at random or email your teacher
anonymous
  • anonymous
okay i think im going to go with 8
Astrophysics
  • Astrophysics
Post the full question
Astrophysics
  • Astrophysics
Maybe you missed a detail
Astrophysics
  • Astrophysics
Including everything
Astrophysics
  • Astrophysics
Yeah ok the options are wrong, go either 8 or cos^2theta I guess :\ make sure to tell your teacher
anonymous
  • anonymous
tahts all it is
anonymous
  • anonymous
do you mind helping w another
Astrophysics
  • Astrophysics
sure
anonymous
  • anonymous
what is the sine value of 5pi/3
anonymous
  • anonymous
i know its equal to 300 degrees
anonymous
  • anonymous
?
Astrophysics
  • Astrophysics
\[\sin(5 \pi/3) \] ok so we have this, the reference angle here is pi/3 what's the ratio of sin(theta)?
anonymous
  • anonymous
im not sure
anonymous
  • anonymous
im sorry im really bad at math i just know tis equal to 300 degrees
Astrophysics
  • Astrophysics
SOH CAH TOA
Astrophysics
  • Astrophysics
that ring a bell?
Astrophysics
  • Astrophysics
\[\sin( \theta) = \frac{ opposite }{ hypotenuse } = \frac{ x }{ r }\]
anonymous
  • anonymous
oh yeah
Astrophysics
  • Astrophysics
|dw:1439605676428:dw| this is the pi/3 triangle, so far so good?
anonymous
  • anonymous
yes
Astrophysics
  • Astrophysics
Ok since we know it's 300 degrees we know it's in the fourth quadrant of unit circle right. So\[y=-\sqrt{3}\]and\[r = 2\]\[\frac{ y }{ r } = \frac{ - \sqrt{3} }{ 2 }\] sorry I put x as opposite when it should be y/r and not x/r.
anonymous
  • anonymous
okay
Astrophysics
  • Astrophysics
So that's our exact value
anonymous
  • anonymous
thank you so much
Astrophysics
  • Astrophysics
Np

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