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anonymous

  • one year ago

(cos Θ + cos Θ)^2 + (cos Θ + cos Θ)^2 answers are sin2 Θ 4 8 cos2 Θ

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  1. anonymous
    • one year ago
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    SOMEONE PLEASE HELP

  2. Astrophysics
    • one year ago
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    I just showed you this :\

  3. Astrophysics
    • one year ago
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    Someone else isn't going to get a different answer...they will tell you your options are wrong as well, we got \[8 \cos^2(\theta)\]

  4. anonymous
    • one year ago
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    yes but i was hoping someone cou;d help me answer it maybe theres a different way

  5. Astrophysics
    • one year ago
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    \[(\cos(\theta)+\cos(\theta)^2 = (2\cos \theta)^2 = 4\cos^2(\theta)\] since both sides are same we have \[4\cos^2(\theta)+4\cos^2(\theta) = 8\cos^2(\theta)\]

  6. Astrophysics
    • one year ago
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    Your options don't make sense, either you just pick one at random or email your teacher

  7. anonymous
    • one year ago
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    okay i think im going to go with 8

  8. Astrophysics
    • one year ago
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    Post the full question

  9. Astrophysics
    • one year ago
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    Maybe you missed a detail

  10. Astrophysics
    • one year ago
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    Including everything

  11. anonymous
    • one year ago
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  12. Astrophysics
    • one year ago
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    Yeah ok the options are wrong, go either 8 or cos^2theta I guess :\ make sure to tell your teacher

  13. anonymous
    • one year ago
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    tahts all it is

  14. anonymous
    • one year ago
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    do you mind helping w another

  15. Astrophysics
    • one year ago
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    sure

  16. anonymous
    • one year ago
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    what is the sine value of 5pi/3

  17. anonymous
    • one year ago
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    i know its equal to 300 degrees

  18. anonymous
    • one year ago
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    ?

  19. Astrophysics
    • one year ago
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    \[\sin(5 \pi/3) \] ok so we have this, the reference angle here is pi/3 what's the ratio of sin(theta)?

  20. anonymous
    • one year ago
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    im not sure

  21. anonymous
    • one year ago
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    im sorry im really bad at math i just know tis equal to 300 degrees

  22. Astrophysics
    • one year ago
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    SOH CAH TOA

  23. Astrophysics
    • one year ago
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    that ring a bell?

  24. Astrophysics
    • one year ago
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    \[\sin( \theta) = \frac{ opposite }{ hypotenuse } = \frac{ x }{ r }\]

  25. anonymous
    • one year ago
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    oh yeah

  26. Astrophysics
    • one year ago
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    |dw:1439605676428:dw| this is the pi/3 triangle, so far so good?

  27. anonymous
    • one year ago
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    yes

  28. Astrophysics
    • one year ago
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    Ok since we know it's 300 degrees we know it's in the fourth quadrant of unit circle right. So\[y=-\sqrt{3}\]and\[r = 2\]\[\frac{ y }{ r } = \frac{ - \sqrt{3} }{ 2 }\] sorry I put x as opposite when it should be y/r and not x/r.

  29. anonymous
    • one year ago
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    okay

  30. Astrophysics
    • one year ago
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    So that's our exact value

  31. anonymous
    • one year ago
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    thank you so much

  32. Astrophysics
    • one year ago
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    Np

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