A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°
anonymous
 one year ago
Determine two pairs of polar coordinates for the point (5, 5) with 0° ≤ θ < 360°

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hey i actually got stuck @Astrophysics

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, no worries, where did you get stuck?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I will just put this for a reference \[x = r \cos \theta\]\[y= r \sin \theta\]\[r^2 = x^2+y^2 \implies r = \sqrt{x^2+y^2}\], and lets go over it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so i plugged in everything... r=sqrt(5^2 + (5)^2) but when i solved for theta my answer wasnt one of the options

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok lets see, so you did \[r = \sqrt{x^2+y^2} \implies r = \sqrt{(5)^2+(5)^2} = \sqrt{50} = 5\sqrt{2}\] so far so good?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok cool, so the angles can be quite tricky that's why I had drawn the triangle for you earlier, so here we have to use the tan ratio to find the angle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so tan(theta) = 5/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0tan(theta) = 1 from here to I inverse it?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup \[\theta = \tan^{1}(1)\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Good so that is 315 degrees

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so it would be 5sqrt(2),315

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, and the other you want for \[5\sqrt{2}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Which is just 315180

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much for the help! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x is positive and y is negative so it is below xaxis x is positive , yis negative ,hence in fourth quadrant.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup I already had shown that in the previous post ;P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you mind helping me with one more? sorry. lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find all polar coordinates of point P = (2, 14°)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x = 1.94059 y = 0.48384

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok maybe I shouldn't have wrote that just ignore it and look at what I said after

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it just be (2, 14 +/ 2npi) ???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes that works (2, 14 +360n) as we're using degrees

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1yes or (2, 14+90+360n)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait im confused now where did the 90 come from?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Look at what I said twice, the polar representations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so all the polar coordinates are (2, 14 +360n) , (2, 14+90+360n)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes that sounds good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks again. for all the help

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1The polar representation should be \[(r, \theta) = (r, \theta+2 \pi n)~~~\text{and}~~~(r, \theta+(2n+1) \pi)\] I think I made a mistake, but your answers are right in any case

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1wait wait that should be an OR not an AND haha ok

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok have fun and take care haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you too. Thanks again
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.