anonymous
  • anonymous
Find the product of the complex numbers. Express your answer in trigonometric form. z1=3(cos(pi/4)+i sin(pi/4)) z2=7(cos(3pi/8)+i sin(3pi/8))
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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tkhunny
  • tkhunny
Have you considered multiplying the leading coefficients and adding the angles?
anonymous
  • anonymous
so 3*7?
tkhunny
  • tkhunny
Now, the second part.

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anonymous
  • anonymous
multiply pi/4*pi/4?
tkhunny
  • tkhunny
Read my first post.
anonymous
  • anonymous
Add pi/4+pi/4?
tkhunny
  • tkhunny
Why would you do that? When you came up with 3*7, you took a value from each of z1 and z2. You should do the same with the addition.
anonymous
  • anonymous
you add 3 and 7? is that what you're saying?
tkhunny
  • tkhunny
No, Please don't reverse correct things you did already. Multiply the leading constants: 3*7 -- Done. Don't change that. Add the angles: ?? + ??
anonymous
  • anonymous
ok I think I understand I use the unit circle to figure out the angle then I add?
tkhunny
  • tkhunny
?? The angles are given. Why do you need a unit circle? \(\dfrac{\pi}{4}+\dfrac{3\pi}{8}\) -- Go!
anonymous
  • anonymous
5pi/8
tkhunny
  • tkhunny
Now, if this happens to be greater than \(2\pi\), you might need that Unit Circle. What is your final answer? You have all the pieces.
anonymous
  • anonymous
So do I do 21cos(5pi/8)+i sin(5pi/8) ?
tkhunny
  • tkhunny
Not quite. The parentheses are not optional.
anonymous
  • anonymous
21(cos(5pi/8)+i sin(5pi/8))
tkhunny
  • tkhunny
Perfect.
anonymous
  • anonymous
okay let me solve
tkhunny
  • tkhunny
Solve what? You are done. Move on to the next one.
anonymous
  • anonymous
oh that's it?
tkhunny
  • tkhunny
That's all there is to it. :-)
anonymous
  • anonymous
thanks

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