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Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name the appropriate geometric figures.
I'm not looking for direct answers, I'd just appreciate a nudge or two.
A double negation, yeah? Isn't that basically indirectly proving?
Wouldn't that rely on the lines being parallel?
Oh, I see what you mean
where is the question?
Sorry, Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name the appropriate geometric figures.
It's not a question, it's a command. That's all that's given. I think I'm proving the converse of the triangle proportionality theorem.
Ooh I could probably say the triangles are similar, thus having congruent angles, then say by extension or by that they're exterior or interior angles or whatever that they're parallel.
we can start with one type of triangle like right-triangle and then use tangent ratio and prove
Do you see what I'm saying? Is that process flawed?
ya you can use that or start with that similar triangles provide congruence
It seems the least convoluted way I've thought.
Could I use the converse(inverse maybe? I forget) of the corresponding angles theorem after saying they're similar to prove parallelism?