A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Challenging Hyperbolic Proof:
anonymous
 one year ago
Challenging Hyperbolic Proof:

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Prove that \[\frac{ 1+tanhx }{ 1tanhx }=e ^{2x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Medal and fans for first. Already know it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think it's just tedious algebra. Using the definition of tanh(x) = {e^x  e^(x)] / (e^x + e^x), substitute back into the equation and simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You do not need (e^xe^x)/(e^x+e^x) to solve at all. To prove it, it must be gone.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I mean to prove it faster without tedious algebra, it should be gone.

Empty
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\cosh x }{\cosh x}\frac{ 1+\tanh x }{ 1\tanh x }=\frac{\cosh x + \sinh x}{\cosh x  \sinh x} = \frac{e^x}{e^{x}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You missed a between the first and second, but that seems reasonable.

Empty
 one year ago
Best ResponseYou've already chosen the best response.1What step? I skipped several steps but they were simple so no point in wasting time typing :P

Empty
 one year ago
Best ResponseYou've already chosen the best response.1If you want me to elaborate on my reasoning anywhere I can explain myself. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439616015632:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just to clarify. Its all good.

Empty
 one year ago
Best ResponseYou've already chosen the best response.1I think the bigger jump is this one: \[\cosh x  \sinh x = e^{x}\] since it's kind of subtle to see how this is true. \[\cosh x = \cosh x\] and \[\sinh x = \sinh x\] so we can plug these in to get it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea and that fact that sinhx+coshx=e^x while coshxsinhx=e^x
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.