anonymous
  • anonymous
Evaluate x^2-6x+13=0 and tell whether or not it is extraneous
Linear Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
We can solve this equation by completing the square since it doesn't factor. 1) x^2-6x =13 2) x^2-6x+ 9 =13+9 3) (x-3)^2=22 4) x-3=+/-sq rt( 22) 5) x=3 +/- sq rt(22)
anonymous
  • anonymous
@mackenzie_willa
wolf1728
  • wolf1728
To determine if it has real or imaginary roots, you take a part of the quadratic formula: Square Root (b^2 -4*a*c) In this quadratic a=1 b=-6 and c=13 Square Root (6^2 -4*1*13) Square Root (36 -52) Square Root (-16) You must take a negative square root and therefore the roots are complex (or imaginary).

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wolf1728
  • wolf1728
geny55's solution is wrong To complete the square the equation should be set up as 1) x^2-6x =MINUS 13 2) x^2-6x+ 9 = -13+9 and then continue from there
anonymous
  • anonymous
hey @wolf1728 can you help me with like 12 math questions please? :)
wolf1728
  • wolf1728
TWELVE math questions? I could help you with a couple
anonymous
  • anonymous
but they are easy math questions :) please help with 12 :)
wolf1728
  • wolf1728
Well at least a few. By the way, why not start a new topic?
anonymous
  • anonymous
or how about science questions? are you good in science?
wolf1728
  • wolf1728
I know science pretty well too
anonymous
  • anonymous
ok awesome.. ill tag you :)
wolf1728
  • wolf1728
Okay

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