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anonymous
 one year ago
Evaluate and tell if it is extraneous or not. x^26x+13=0
anonymous
 one year ago
Evaluate and tell if it is extraneous or not. x^26x+13=0

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step 1 : Raise x to the 2nd power

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is the Equation at the end of step 1 : (x2  6x) + 13 = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Step 2 : Simplify x26x + 13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Equation at the end of step 2 : x2  6x + 13 = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what would the answer be? bc i factored it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplifying x2 + 6x + 13 = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Reorder the terms: 13 + 6x + x2 = 0 Solving 13 + 6x + x2 = 0 Solving for variable 'x'. Begin completing the square. Move the constant term to the right: Add '13' to each side of the equation. 13 + 6x + 13 + x2 = 0 + 13 Reorder the terms: 13 + 13 + 6x + x2 = 0 + 13 Combine like terms: 13 + 13 = 0 0 + 6x + x2 = 0 + 13 6x + x2 = 0 + 13 Combine like terms: 0 + 13 = 13 6x + x2 = 13 The x term is 6x. Take half its coefficient (3). Square it (9) and add it to both sides. Add '9' to each side of the equation. 6x + 9 + x2 = 13 + 9 Reorder the terms: 9 + 6x + x2 = 13 + 9 Combine like terms: 13 + 9 = 4 9 + 6x + x2 = 4 Factor a perfect square on the left side: (x + 3)(x + 3) = 4 Can't calculate square root of the right side. The solution to this equation could not be determined.
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