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anonymous

  • one year ago

Evaluate and tell if it is extraneous or not. x^2-6x+13=0

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  1. anonymous
    • one year ago
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    @geny55

  2. anonymous
    • one year ago
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    Step 1 : Raise x to the 2nd power

  3. anonymous
    • one year ago
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    factor?

  4. anonymous
    • one year ago
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    this is the Equation at the end of step 1 : (x2 - 6x) + 13 = 0

  5. anonymous
    • one year ago
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    Step 2 : Simplify x2-6x + 13

  6. anonymous
    • one year ago
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    3+ or - 2i

  7. anonymous
    • one year ago
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    Equation at the end of step 2 : x2 - 6x + 13 = 0

  8. anonymous
    • one year ago
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    ok:)

  9. anonymous
    • one year ago
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    so what would the answer be? bc i factored it

  10. anonymous
    • one year ago
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    Simplifying x2 + 6x + 13 = 0

  11. anonymous
    • one year ago
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    Reorder the terms: 13 + 6x + x2 = 0 Solving 13 + 6x + x2 = 0 Solving for variable 'x'. Begin completing the square. Move the constant term to the right: Add '-13' to each side of the equation. 13 + 6x + -13 + x2 = 0 + -13 Reorder the terms: 13 + -13 + 6x + x2 = 0 + -13 Combine like terms: 13 + -13 = 0 0 + 6x + x2 = 0 + -13 6x + x2 = 0 + -13 Combine like terms: 0 + -13 = -13 6x + x2 = -13 The x term is 6x. Take half its coefficient (3). Square it (9) and add it to both sides. Add '9' to each side of the equation. 6x + 9 + x2 = -13 + 9 Reorder the terms: 9 + 6x + x2 = -13 + 9 Combine like terms: -13 + 9 = -4 9 + 6x + x2 = -4 Factor a perfect square on the left side: (x + 3)(x + 3) = -4 Can't calculate square root of the right side. The solution to this equation could not be determined.

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