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marigirl
 one year ago
Plz check my work
The depth of water h, is meters at the entrance to a harbour t hours after midnight can be modelled by the equation h=5+2.6cos 4*pi*t/25.
At what rate is the depth of the water changing at 10 am?
So dh/dt= 1.3069sin (4*pi*t/25)
Which is correct
Then to find depth of water change we substitute t=10 yes?
When I did I get 0.114
Which doesn't make sense??
ANSWER says:at t=10 dh/dt= 1.24m
marigirl
 one year ago
Plz check my work The depth of water h, is meters at the entrance to a harbour t hours after midnight can be modelled by the equation h=5+2.6cos 4*pi*t/25. At what rate is the depth of the water changing at 10 am? So dh/dt= 1.3069sin (4*pi*t/25) Which is correct Then to find depth of water change we substitute t=10 yes? When I did I get 0.114 Which doesn't make sense?? ANSWER says:at t=10 dh/dt= 1.24m

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you got the derivative right. Just did the algebra wrong when you plugged 10 in for t.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If you used a calculator, make sure it's in radian mode

marigirl
 one year ago
Best ResponseYou've already chosen the best response.0Oh yes radian mode... how could I forget .. lol Thanks
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