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marigirl

  • one year ago

Plz check my work The depth of water h, is meters at the entrance to a harbour t hours after midnight can be modelled by the equation h=5+2.6cos 4*pi*t/25. At what rate is the depth of the water changing at 10 am? So dh/dt= -1.3069sin (4*pi*t/25) Which is correct Then to find depth of water change we substitute t=10 yes? When I did I get -0.114 Which doesn't make sense?? ANSWER says:at t=10 dh/dt= 1.24m

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  1. anonymous
    • one year ago
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    you got the derivative right. Just did the algebra wrong when you plugged 10 in for t.

  2. anonymous
    • one year ago
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    If you used a calculator, make sure it's in radian mode

  3. marigirl
    • one year ago
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    Oh yes radian mode... how could I forget .. lol Thanks

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