## anonymous one year ago You are in a hot-air balloon that, relative to the ground, has a velocity of 6.65 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 2.88 m/s. What are (a) the magnitude and (b) direction of the hawk's velocity relative to the ground? Express the directional angle relative to due east.

1. anonymous

Use pythagorean theorem to find magnitude and use $\tan^{-1} (\frac{ y }{ x })$ to find the angle

2. arindameducationusc

you there @neelam.khindria ?

3. anonymous

Is it correct? @arindameducationusc |dw:1439620341819:dw|

4. anonymous

Never got tested on relative velocity or acceleration.

5. arindameducationusc

theta=tan inverse(y/x) yes @Shalante you are right....

6. anonymous

Thanks for the response

7. anonymous

thanks guys!

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