Mimi_x3
  • Mimi_x3
i have problems with finding eigen vectors
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mimi_x3
  • Mimi_x3
https://gyazo.com/355c33166a1edf8139c5331e6e525dc0
Mimi_x3
  • Mimi_x3
i get stuck here|dw:1439628997200:dw|
Mimi_x3
  • Mimi_x3
is there like a legitmate resource in finding eigen vectors

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Empty
  • Empty
Crap it cut off your vector there on the equal sign
Mimi_x3
  • Mimi_x3
i feel as though i'm just guessing
Empty
  • Empty
I'm a legitimate resource bb
Mimi_x3
  • Mimi_x3
crap what
Mimi_x3
  • Mimi_x3
bb you're never there for me
Empty
  • Empty
|dw:1439629120440:dw|
Mimi_x3
  • Mimi_x3
IM UNDATEABLE APPARRENTLY
Mimi_x3
  • Mimi_x3
oh |dw:1439629144430:dw|
Empty
  • Empty
Shhhh I'm trying to help you eigenvectorsize
Mimi_x3
  • Mimi_x3
pls do... I have no idea with this course
Mimi_x3
  • Mimi_x3
|dw:1439629180128:dw|
Empty
  • Empty
Ok so first off, just multiply the vector with the first row of this matrix. What do you get?
Mimi_x3
  • Mimi_x3
-3iv1 = -3v2 v_1 = - iv_2
Mimi_x3
  • Mimi_x3
v_2 = iv_1
Empty
  • Empty
Perfect, so now we can plug this in to your vector (v_1, v_2) to get this: |dw:1439629321422:dw|
Mimi_x3
  • Mimi_x3
WAIT
Mimi_x3
  • Mimi_x3
isnt v_2 = iv_1
Empty
  • Empty
So your eigenvector is (-i, 1), and the v_2 is just an arbitrary constant showing you you can multiply your eigenvector by any constant. So now multiply your vector by i and see it desn't matter: |dw:1439629416364:dw|
Mimi_x3
  • Mimi_x3
omg you're a god
Empty
  • Empty
;) yw bb
Mimi_x3
  • Mimi_x3
can you be here for me
Empty
  • Empty
i AM here 4 u
Mimi_x3
  • Mimi_x3
https://gyazo.com/57ff65da1ee195dad40b72621f15dca7
Mimi_x3
  • Mimi_x3
I don't get the formula for one real value
Mimi_x3
  • Mimi_x3
https://gyazo.com/cbb81b2511c7aa5f2042c6ddd3d3389f
Mimi_x3
  • Mimi_x3
what is that 1 I thing doing
Empty
  • Empty
Oh I don't know I need to solve it give me a sec unless you have something solved
Mimi_x3
  • Mimi_x3
|dw:1439629654953:dw|
Mimi_x3
  • Mimi_x3
the eigen vector
Mimi_x3
  • Mimi_x3
so now plugging into the formula which i don't get
Empty
  • Empty
so wait real fast you're asking: |dw:1439629691610:dw|
Mimi_x3
  • Mimi_x3
isn't that suppose to be 0 0
Mimi_x3
  • Mimi_x3
I'm asking how to plug into formula
Mimi_x3
  • Mimi_x3
https://gyazo.com/e5a65ed4111fcbcb257ed0465a3efaba
Empty
  • Empty
I don't know, I need to review it's been a while since I've done these so I kinda forget like minor stuff.
Mimi_x3
  • Mimi_x3
I have solution
Mimi_x3
  • Mimi_x3
which i don't get
Empty
  • Empty
what's that fancy 1, like I think it's a vector with two 1s in it? |dw:1439629848428:dw|
Mimi_x3
  • Mimi_x3
no idea
Mimi_x3
  • Mimi_x3
I HAVE NOT TAKEN MATHS FOR 2 years :((((
Empty
  • Empty
It's ok I'll help figure it out. I know that repeated eigenvalues are weird though, so you might just have to memorize this trick, I think you just multiply by t honestly they're making it look more complicated than it should be I think cause they're retarded
Mimi_x3
  • Mimi_x3
|dw:1439629912004:dw|
Mimi_x3
  • Mimi_x3
ok i get above^ just plugging in
Mimi_x3
  • Mimi_x3
|dw:1439629999156:dw|
Mimi_x3
  • Mimi_x3
I HAVE NO CLUE FOR THIS PART^
Empty
  • Empty
Ok I think I got it give me a sec I don't wanna tell you wrong stuff
Mimi_x3
  • Mimi_x3
ok
Empty
  • Empty
Ok ok, so now we can multiply to get: |dw:1439630308680:dw| I think that should work
Mimi_x3
  • Mimi_x3
yeah
Mimi_x3
  • Mimi_x3
but i don't get how u got to it
Empty
  • Empty
ok circle the steps that don't make sense
Mimi_x3
  • Mimi_x3
|dw:1439630519158:dw|
Mimi_x3
  • Mimi_x3
from here |dw:1439630544936:dw|
Empty
  • Empty
oh ok I forgot to include that! I realized that fancy 1 was the identity matrix: |dw:1439630629121:dw| then plugging in from there we have: |dw:1439630686461:dw| so that's what leads to this step here: |dw:1439630539112:dw| I kinda skipped some steps but circle anything else that bothers you so I can explain it more. ;)
Empty
  • Empty
I gotta go to sleep soon
Empty
  • Empty
gn bb xoxo
Mimi_x3
  • Mimi_x3
:( you left me
Mimi_x3
  • Mimi_x3
BUT THANK YOUUU LOVE U FOR LIFE
Mimi_x3
  • Mimi_x3
if you do come back
Mimi_x3
  • Mimi_x3
https://gyazo.com/2106cd0c4185f371f26e9a1ed67e7d0c i don't get this one
phi
  • phi
It is not clear how to proceed other than "pattern match" \[ \dot{x}_1 =x_1+x_2\\ \dot{y}_1= y_2 \] and try \(y_2= x_1+x_2\) from which we get \( \dot{y}_2= \dot{x}_1+ \dot{x}_2\) also, the second equation is \[ \dot{x}_2 =-2x_1-x_2\] adding this to the first \[ \dot{x}_1 =x_1+x_2 \] we get \[ \dot{x}_1 +\dot{x}_2=x_1+x_2-2x_1-x_2 =-x_1 \] or, using our "guess" \[ \dot{y}_2= - x_1 \] which is consistent with \(y_1= x_1\) in other words, make the substitutions \[ x_1= y_1 \\ y_2= x_1+x_2 \rightarrow x_2= y_2 -y_1\]

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