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anonymous

  • one year ago

a bicyclist starts from rest and accelerates at 2 rad/s2. In 10 seconds what is the angular velocity of the bike wheels and how many revolutions has the bike wheels completed?

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  1. anonymous
    • one year ago
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    @ganeshie8

  2. anonymous
    • one year ago
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    @Frostbite @UsukiDoll

  3. UsukiDoll
    • one year ago
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    I'm bad at physics :(

  4. anonymous
    • one year ago
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    me too :( thanks anyway my friend :D

  5. anonymous
    • one year ago
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    i have an attempt at the solution :)

  6. anonymous
    • one year ago
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    i'll post it?

  7. arindameducationusc
    • one year ago
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    Can I try?

  8. anonymous
    • one year ago
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    :D okay

  9. arindameducationusc
    • one year ago
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    Just check....

  10. arindameducationusc
    • one year ago
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    one second I did a mistake......

  11. arindameducationusc
    • one year ago
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    use w^2=2*alpha*t where alpha=2, t=10

  12. arindameducationusc
    • one year ago
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    sqrt(40) is angular velocity Check it.... i am pretty sure

  13. anonymous
    • one year ago
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    6.324 you mean? i got 20 rad/s

  14. arindameducationusc
    • one year ago
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    hmmm....

  15. IrishBoy123
    • one year ago
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    |dw:1439636369189:dw| post the actual question or a link ??!!

  16. arindameducationusc
    • one year ago
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    yes its 20.... we get s=100 and putting in v^2-u^2=2*aplha*s we get sqrt(400) which is 20

  17. arindameducationusc
    • one year ago
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    we get s=100 bu s=1/2*alpha*t^2

  18. arindameducationusc
    • one year ago
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    yes you are right @KarlaKalurky

  19. anonymous
    • one year ago
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    haha @IrishBoy123 that's as nice joke :D

  20. arindameducationusc
    • one year ago
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    w=2*pi*f where f is the frequency

  21. arindameducationusc
    • one year ago
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    20=2*pi*f f=10/pi

  22. anonymous
    • one year ago
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    what are the formulas to solve for no. of rev?

  23. arindameducationusc
    • one year ago
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    w=2*pi/T where w=20 we get T=pi/10 (for one cycle)

  24. anonymous
    • one year ago
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    100 rad(1rev/(2pi)rad) = 15.9155 rev ?

  25. arindameducationusc
    • one year ago
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    hmmm.... let me think....

  26. arindameducationusc
    • one year ago
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    wait.... I got it... w=2*pi*f 20/2*pi=f 3.18 revolution in one second so 10 second, 10*3.18=31.8

  27. arindameducationusc
    • one year ago
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    This should be the answer @KarlaKalurky

  28. anonymous
    • one year ago
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    thank you very much! :D

  29. arindameducationusc
    • one year ago
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    no problem

  30. IrishBoy123
    • one year ago
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    you need the angular analogues of the equations of motion \(v = u + at \\x = ut + \frac {1}{2} a t^2 \\ v^2 = u^2 + 2 ax\) which are \(\omega_2 = \omega_1 + \alpha t \\\theta = \omega_1t + \frac {1}{2} \alpha t^2 \\ \omega_2^2 = \omega_1^2 + 2 \alpha \theta\)

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