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anonymous
 one year ago
a bicyclist starts from rest and accelerates at 2 rad/s2. In 10 seconds what is the angular velocity of the bike wheels and how many revolutions has the bike wheels completed?
anonymous
 one year ago
a bicyclist starts from rest and accelerates at 2 rad/s2. In 10 seconds what is the angular velocity of the bike wheels and how many revolutions has the bike wheels completed?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Frostbite @UsukiDoll

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1I'm bad at physics :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0me too :( thanks anyway my friend :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have an attempt at the solution :)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Can I try?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Just check....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1one second I did a mistake......

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1use w^2=2*alpha*t where alpha=2, t=10

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1sqrt(40) is angular velocity Check it.... i am pretty sure

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06.324 you mean? i got 20 rad/s

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439636369189:dw post the actual question or a link ??!!

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes its 20.... we get s=100 and putting in v^2u^2=2*aplha*s we get sqrt(400) which is 20

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1we get s=100 bu s=1/2*alpha*t^2

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1yes you are right @KarlaKalurky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha @IrishBoy123 that's as nice joke :D

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1w=2*pi*f where f is the frequency

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.120=2*pi*f f=10/pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what are the formulas to solve for no. of rev?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1w=2*pi/T where w=20 we get T=pi/10 (for one cycle)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0100 rad(1rev/(2pi)rad) = 15.9155 rev ?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1hmmm.... let me think....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1wait.... I got it... w=2*pi*f 20/2*pi=f 3.18 revolution in one second so 10 second, 10*3.18=31.8

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1This should be the answer @KarlaKalurky

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you very much! :D

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1no problem

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you need the angular analogues of the equations of motion \(v = u + at \\x = ut + \frac {1}{2} a t^2 \\ v^2 = u^2 + 2 ax\) which are \(\omega_2 = \omega_1 + \alpha t \\\theta = \omega_1t + \frac {1}{2} \alpha t^2 \\ \omega_2^2 = \omega_1^2 + 2 \alpha \theta\)
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