anonymous
  • anonymous
I need help with this question. It is similarity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
question 3
anonymous
  • anonymous
the answer for 3a. is 15:16, 225:256

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anonymous
  • anonymous
and for 3b. 1:20, 1:400
anonymous
  • anonymous
\[\frac{ 7 }{ 0.875 } = \frac{ x }{ 0.7 }\]
anonymous
  • anonymous
where did u get 0.7
anonymous
  • anonymous
oh wait i did your question 4
anonymous
  • anonymous
lel
anonymous
  • anonymous
oh its only questions 3
anonymous
  • anonymous
This is wat i did, but it is not the same as the answer
anonymous
  • anonymous
because \[(\frac{ 0.875 }{ 7 } ) ^3 = \frac{ 1 }{ 512 }\]
anonymous
  • anonymous
where did u get 512
anonymous
  • anonymous
calculator
anonymous
  • anonymous
0.875 divide by 7 then cube
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
but why do i need to do that
anonymous
  • anonymous
you did your\[(\frac{ s_1 }{ s_2 })^3\]the wrong way
anonymous
  • anonymous
how can\[(\frac{ 0.875 }{ 7 })^3 = 1/2\]
anonymous
  • anonymous
no i want to find the ratio for the sides which is s1/s2
anonymous
  • anonymous
so I cube root the volume
anonymous
  • anonymous
i know but you made a calculation error there
anonymous
  • anonymous
but \[\sqrt[3]{\frac{ 0.875 }{ 7}} = \frac{ 1 }{ 2}\]
anonymous
  • anonymous
yup
anonymous
  • anonymous
then why is it a calculation error
anonymous
  • anonymous
i thought you cube that 0.875/7
anonymous
  • anonymous
ohhhh
anonymous
  • anonymous
anyways so I found the ratio of a side on the smaller solid to the corresponding side on the larger solid which is 1:2 but the answers say that it is 15:16
anonymous
  • anonymous
they are asking for ratio of surface area
anonymous
  • anonymous
not ratio of sides
anonymous
  • anonymous
weird stuff!
anonymous
  • anonymous
it says to do both
anonymous
  • anonymous
if the ratio of side is 15/16 then ratio of area is (15/16)^2
anonymous
  • anonymous
why?
anonymous
  • anonymous
http://www.bbc.co.uk/schools/gcsebitesize/maths/geometry/congruencysimilarityrev4.shtml

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