## anonymous one year ago The automobile has a speed of 80 ft/s and an acceleration a of magnitude 10 ft/s2 in the direction shown when it is at point A. Determine the radius of curvature of the path at point A, and the tangential component of acceleration. (Ans. ρ = 1280 ft)

1. anonymous

2. anonymous

$a = \frac{ v^2 }{ \rho }$ you need to use the component of a in the normal direction |dw:1439641571882:dw|

3. arindameducationusc

r=v^2/a*cos(60) r=6400/10*(1/2) =1280

4. IrishBoy123

as this is a physics board, i am allowed to ask this does anyone know what a radius of curvature actually means in the physical sense?

5. anonymous

I don't know that it means anything physically. It's taking a portion of a curve to approximate a circle, and the radius of curvature is the radius of said circle, crudely speaking.

6. anonymous