Write the equation of an ellipse with vertices (0, 5) and (0, -5) and co-vertices (2, 0) and (-2, 0).

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Write the equation of an ellipse with vertices (0, 5) and (0, -5) and co-vertices (2, 0) and (-2, 0).

Mathematics
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|dw:1439646942183:dw|
a=5 b=2
5^2=25 2^2=4

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Other answers:

y2/25 + x2/4 = 1? the horizontal get me mixed up sometimes but i feel thats right
How to say!!! You are an EXPERT now. hehehe
only bc u took the time to teach my slow mind lol thank you, now..can u teach me hyperbola? those confuess me more then anything @Loser66
Let's look at it first. I am not sure whether I can or not. One more thing, you have only 15 more minutes. I have to go after then.
one more thing! Ellipses have symmetry through only their major axis? true or false? lol
i think its false?
through both axis
so its false
yup
To hyperbola, everything is the same with ellipse but the - sign
okay. ill start a new post.
a goes with main axis b goes with co-axis. and c^2 = a^2 + b^2 (opposite with ellipse, which is c^2 =a^2 -b^2\)
why a new post. It is good here
okay- What are the asymptotes of the following graph?
|dw:1439647512939:dw|
|dw:1439647585256:dw|
ok, |dw:1439647624382:dw|
Do you know how to find the slope of this line?
one sec.
m=y1-y2/x1-x2
yes, =?
m=-3-3/-1-1
nope
You plug in x1-x2 on top. it is not right,
y=-1-1/-3-3
yup, =?
m=-2/-6 m=2/6 m=1/3
Bingo
Hence the asymptote of the hyperbola is just \(y =\pm\dfrac{1}{3}x\)
okay i get it. can we get 1 more in really quickly?
3 minutes for that.
What is the center of the following graph?
|dw:1439648000091:dw|
(1,2)
yup
u think we can solve for a foci or not enough time?
not enough
but I can give you a guidance: find asymptote, it is the form of a/b, take that a, b to solve for c which is foci.

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