anonymous
  • anonymous
Write the equation of an ellipse with vertices (0, 5) and (0, -5) and co-vertices (2, 0) and (-2, 0).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1439646942183:dw|
anonymous
  • anonymous
a=5 b=2
anonymous
  • anonymous
5^2=25 2^2=4

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anonymous
  • anonymous
y2/25 + x2/4 = 1? the horizontal get me mixed up sometimes but i feel thats right
Loser66
  • Loser66
How to say!!! You are an EXPERT now. hehehe
anonymous
  • anonymous
only bc u took the time to teach my slow mind lol thank you, now..can u teach me hyperbola? those confuess me more then anything @Loser66
Loser66
  • Loser66
Let's look at it first. I am not sure whether I can or not. One more thing, you have only 15 more minutes. I have to go after then.
anonymous
  • anonymous
one more thing! Ellipses have symmetry through only their major axis? true or false? lol
anonymous
  • anonymous
i think its false?
Loser66
  • Loser66
through both axis
anonymous
  • anonymous
so its false
Loser66
  • Loser66
yup
Loser66
  • Loser66
To hyperbola, everything is the same with ellipse but the - sign
anonymous
  • anonymous
okay. ill start a new post.
Loser66
  • Loser66
a goes with main axis b goes with co-axis. and c^2 = a^2 + b^2 (opposite with ellipse, which is c^2 =a^2 -b^2\)
Loser66
  • Loser66
why a new post. It is good here
anonymous
  • anonymous
okay- What are the asymptotes of the following graph?
Loser66
  • Loser66
|dw:1439647512939:dw|
anonymous
  • anonymous
|dw:1439647585256:dw|
Loser66
  • Loser66
ok, |dw:1439647624382:dw|
Loser66
  • Loser66
Do you know how to find the slope of this line?
anonymous
  • anonymous
one sec.
anonymous
  • anonymous
m=y1-y2/x1-x2
Loser66
  • Loser66
yes, =?
anonymous
  • anonymous
m=-3-3/-1-1
Loser66
  • Loser66
nope
Loser66
  • Loser66
You plug in x1-x2 on top. it is not right,
anonymous
  • anonymous
y=-1-1/-3-3
Loser66
  • Loser66
yup, =?
anonymous
  • anonymous
m=-2/-6 m=2/6 m=1/3
Loser66
  • Loser66
Bingo
Loser66
  • Loser66
Hence the asymptote of the hyperbola is just \(y =\pm\dfrac{1}{3}x\)
anonymous
  • anonymous
okay i get it. can we get 1 more in really quickly?
Loser66
  • Loser66
3 minutes for that.
anonymous
  • anonymous
What is the center of the following graph?
Loser66
  • Loser66
|dw:1439648000091:dw|
anonymous
  • anonymous
(1,2)
Loser66
  • Loser66
yup
anonymous
  • anonymous
u think we can solve for a foci or not enough time?
Loser66
  • Loser66
not enough
Loser66
  • Loser66
but I can give you a guidance: find asymptote, it is the form of a/b, take that a, b to solve for c which is foci.

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