A community for students.
Here's the question you clicked on:
 0 viewing
ksaimouli
 one year ago
graph inequalities
ksaimouli
 one year ago
graph inequalities

This Question is Closed

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439648281026:dw

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0Is that right, if so what would be the solution

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439648545613:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2start by graphing the corresponding "lines" x+y = 4 y+3x = 6

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439648848102:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2you should get those lines, right ?

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0yes, so the solution the intrsection right?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2the solution is just the intersection point if they are "equalities" but we have inequalities, so no

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0the solution is the shaded region

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2lets do the shading first x+y>4 y > x + 4 so shade the above part for red line : dw:1439649623303:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2do the shading for the other inequality also y+3x<6 y < 3x+6 so shade the bottom part of blue line : dw:1439649749122:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2the solution is the common region of those two shadings

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.0can we express that mathematically?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2sure, you can see that \(x<1\) for the common region, yes ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2and every point in that region is above red line and below blue line : dw:1439651204202:dw