ksaimouli
  • ksaimouli
graph inequalities
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ksaimouli
  • ksaimouli
x+y>4 y+3x<6
ksaimouli
  • ksaimouli
|dw:1439648281026:dw|
ksaimouli
  • ksaimouli
Is that right, if so what would be the solution

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welshfella
  • welshfella
|dw:1439648545613:dw|
ganeshie8
  • ganeshie8
start by graphing the corresponding "lines" x+y = 4 y+3x = 6
ganeshie8
  • ganeshie8
|dw:1439648848102:dw|
ganeshie8
  • ganeshie8
you should get those lines, right ?
ksaimouli
  • ksaimouli
yes, so the solution the intrsection right?
ganeshie8
  • ganeshie8
the solution is just the intersection point if they are "equalities" but we have inequalities, so no
ksaimouli
  • ksaimouli
the solution is the shaded region
ganeshie8
  • ganeshie8
lets do the shading first x+y>4 y > -x + 4 so shade the above part for red line : |dw:1439649623303:dw|
ganeshie8
  • ganeshie8
do the shading for the other inequality also y+3x<6 y < -3x+6 so shade the bottom part of blue line : |dw:1439649749122:dw|
ganeshie8
  • ganeshie8
the solution is the common region of those two shadings
ksaimouli
  • ksaimouli
can we express that mathematically?
ganeshie8
  • ganeshie8
sure, you can see that \(x<1\) for the common region, yes ?
ganeshie8
  • ganeshie8
and every point in that region is above red line and below blue line : |dw:1439651204202:dw|