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ksaimouli

  • one year ago

graph inequalities

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  1. ksaimouli
    • one year ago
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    x+y>4 y+3x<6

  2. ksaimouli
    • one year ago
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    |dw:1439648281026:dw|

  3. ksaimouli
    • one year ago
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    Is that right, if so what would be the solution

  4. welshfella
    • one year ago
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    |dw:1439648545613:dw|

  5. ganeshie8
    • one year ago
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    start by graphing the corresponding "lines" x+y = 4 y+3x = 6

  6. ganeshie8
    • one year ago
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    |dw:1439648848102:dw|

  7. ganeshie8
    • one year ago
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    you should get those lines, right ?

  8. ksaimouli
    • one year ago
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    yes, so the solution the intrsection right?

  9. ganeshie8
    • one year ago
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    the solution is just the intersection point if they are "equalities" but we have inequalities, so no

  10. ksaimouli
    • one year ago
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    the solution is the shaded region

  11. ganeshie8
    • one year ago
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    lets do the shading first x+y>4 y > -x + 4 so shade the above part for red line : |dw:1439649623303:dw|

  12. ganeshie8
    • one year ago
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    do the shading for the other inequality also y+3x<6 y < -3x+6 so shade the bottom part of blue line : |dw:1439649749122:dw|

  13. ganeshie8
    • one year ago
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    the solution is the common region of those two shadings

  14. ksaimouli
    • one year ago
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    can we express that mathematically?

  15. ganeshie8
    • one year ago
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    sure, you can see that \(x<1\) for the common region, yes ?

  16. ganeshie8
    • one year ago
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    and every point in that region is above red line and below blue line : |dw:1439651204202:dw|