Write the equation of a hyperbola with vertices (0, -5) and (0, 5) and co-vertices (-2, 0) and (2, 0).

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Write the equation of a hyperbola with vertices (0, -5) and (0, 5) and co-vertices (-2, 0) and (2, 0).

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1439651369346:dw|
|dw:1439651447111:dw|
y2/25-x2/4=1

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better is: |dw:1439651525956:dw|
okay
ok! correct!
i got the equation right?
right!
in your case the focal axis is the y-axis
Write the equation of a hyperbola with vertices at (-4, 0) and (4, 0) and co-vertices (0, 5) and (0, -5). x2/16-y2/25=1 - correct?
yes! correct!
The symmetry of a hyperbola with a center at (h, k) only occurs at x = h. True?
sorry for the extra question, but im just doulbe checking with u
no its false bc it can occur at both.
yes correct, for example we can consider the cas h,k>0, so we have this drawing: |dw:1439651855400:dw|
so its false?
another symmetry, as you can see from my drawing is with respect to the axis y=k
we have two symmetry axes
so the anwser false? lol im getting confuessed
it is false, since the symmetries occur with respect to these axes: x=h y=k
okay thank you> we are all done with ellipses and hyperbola lol
ok! :)
no we are not.. i went to submit it, and something happen and now half of the questions sre blank god damnit
If you have an exercise about an ellipse or a new hyperbola, then please open a new question, and tag me

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