anonymous
  • anonymous
What is the equation of the following graph?
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Michele_Laino
  • Michele_Laino
that is a traslated ellipse
Michele_Laino
  • Michele_Laino
as you can see from the graph, the center of our ellipse is located at (0,-2)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
y2/9+x2/1
Michele_Laino
  • Michele_Laino
no, since we have to make a traslation
Michele_Laino
  • Michele_Laino
let's consider a new coordinate system X,Y located at point (0,2), namely at the center of your ellipse
Michele_Laino
  • Michele_Laino
with respect to the XY system the equation of our ellipse is: \[\Large \frac{{{X^2}}}{1} + \frac{{{Y^2}}}{9} = 1\]
Michele_Laino
  • Michele_Laino
am I right?
anonymous
  • anonymous
yes
Michele_Laino
  • Michele_Laino
here is the situation of your exercise: |dw:1439652920237:dw|
Michele_Laino
  • Michele_Laino
oops.. I made a typo, the center of our ellipse is located at poin (0,-2)
Michele_Laino
  • Michele_Laino
and the equations of our traslation are: \[\Large \left\{ \begin{gathered} x = X \hfill \\ y = Y - 2 \hfill \\ \end{gathered} \right.\]
anonymous
  • anonymous
okay
Michele_Laino
  • Michele_Laino
now, please solve that system for X, and Y, what do you get?
anonymous
  • anonymous
im lost now.
Michele_Laino
  • Michele_Laino
hint: we have this: \[\Large X = x\] right?
anonymous
  • anonymous
yes
sohailiftikhar
  • sohailiftikhar
what you want to know?
Michele_Laino
  • Michele_Laino
ok! now do the same, namely write Y as a function of y, please
anonymous
  • anonymous
y=y-2 ?
Michele_Laino
  • Michele_Laino
\[\Large Y = y + 2\]
anonymous
  • anonymous
oh okay
Michele_Laino
  • Michele_Laino
next, replace X with x, and Y with y+2 into my equation above
Michele_Laino
  • Michele_Laino
namely into this equation: \[\Large \frac{{{X^2}}}{1} + \frac{{{Y^2}}}{9} = 1\] what equation do you get?
anonymous
  • anonymous
idk im lost again..im glad im going over this other wise i would have gotten this wrong
Michele_Laino
  • Michele_Laino
hint: \[\Large \frac{{{x^2}}}{1} + \frac{{{{\left( {y + 2} \right)}^2}}}{9} = 1\] is it right?
anonymous
  • anonymous
yes
Michele_Laino
  • Michele_Laino
that is the requested equation
anonymous
  • anonymous
so that the anwser?
Michele_Laino
  • Michele_Laino
yes!
Loser66
  • Loser66
For shifted one, you need center (h, k), the way to find out a, b as what we had done before. The way a goes with major axis is the same. Just the numerators change to (x-h) ^2 and (y-k)^2. Dat sit.

Looking for something else?

Not the answer you are looking for? Search for more explanations.