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anonymous
 one year ago
how to verify frac(sec theta/ csc theta cot theta frac(sectheta/csc theta +cot theta = 2csc theta
anonymous
 one year ago
how to verify frac(sec theta/ csc theta cot theta frac(sectheta/csc theta +cot theta = 2csc theta

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \frac{ \sec \theta }{ \csc \theta \cot \theta } \frac{ \sec \theta }{ \csc \theta +\cot \theta }=2\csc \theta \] like this ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1ye gimme a sec let me do it i'll try to find easy way

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay alright so first we should write sec and csc in terms of sin or cos csc = ?? sec equal what ? do you know ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/sin  csc and sec =1/cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right first deal with the denominator\[\large\rm \frac{ \sec \theta }{ \color{ReD}{\csc \theta \cot \theta }} \frac{ \sec \theta }{\color{reD}{ \csc \theta +\cot \theta }}=2\csc \theta \] \[\huge\rm \frac{ \sec \theta }{ \frac{ 1 }{ \sin }\frac{ \cos }{ \sin}}  \frac{ \sec \theta }{ \frac{ 1 }{ \csc }+\frac{ \cos }{ \sin } }\] cot =cos over sin

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes i got that far then i get stuck

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \frac{ \sec \theta }{ \color{red}{\frac{ 1 }{ \sin }\frac{ \cos }{ \sin}}}  \frac{ \sec \theta }{\color{red}{ \frac{ 1 }{ \csc }+\frac{ \cos }{ \sin } }}\] find common denominator of red part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but i get 1/sin +cos/sin

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01cos/sin  1+cos/sin

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1if you have some work show it to me so i can find ur mistakes instead stating ovr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01cos/ sin 1+cos/sin sin/sinsin/sin which equals 1 then i flip it to multiuply with 1/cos1/cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1brb i should refresh the page its lagging

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is where i get lost

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm \frac{ \sec }{ \frac{ 1+\cos }{ \sin } }\frac{ \sec }{ \frac{ 1+\cos }{ \sin } }\]now multiply top with the reciprocal of the bottom fraction (change division to multiplication ) like for first one \[\large\rm \sec \times \frac{ \sin }{ 1\cos }  \sec \times \frac{ \sin }{ 1+\cos }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then I get 1cos(sec) /sin  1+cos(sec)/sin

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right we can change sec to 1 over cos \[\frac{ 1 }{ \cos } \times \frac{ \sin }{ 1\cos }  \frac{ 1 }{ \cos } \times \frac{\sin }{ 1+\cos }\] \[\frac{ \sin }{ \cos(1\cos) } \frac{ \sin }{ \cos (1+\cos) }\] now find the common denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \frac{ \sin\color{reD}{(1+\cos )}\sin\color{reD}{(1\cos)} }{ \cos (1\cos)(1+\cos) }\] multiply sin with the denominator of 2nd fraction and multiply numerator of 2nd fraction with the denominator of 1st fraction that's how i got the red part now distribute parentheses by sin at the top and foil(1cos)(1+cos)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sin+sin cos  sinsin cos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then distribute? sorry wrong

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1sign mistake sin times cos = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes foil (1cos)(1+cos) which is at the denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \frac{ \sin +sincos\sin +sincos }{ \cos(1\cos)(1+\cos) }\] now (1cos)(1+cos ) = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now it's not just cos ^2 dw:1439658869096:dw what do you get when you multiply first term by 1st term of 2nd parentheses

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right yes right \[\huge\rm \frac{ \color{red}{\sin }+sincos\color{reD}{\sin} +sincos }{ \cos(1cos^2) }\] combine like terms (numerator) cos ^2 = ? do you remember the identity \[\sin^2 \theta + \cos^2 \theta=1\] solve this for cos^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hmm no sin sin = ?? sincos + sincos= ?? combine like terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sinsin =0 and sincos+sincos=2sincos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \frac{ 2sincos }{ \cos(1+\cos^2) }\] cos^2=what ? ^identity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pythagorean identity soi have now 2sincos/cos(sin^2)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \sin^2 +\cos^2 =1\] solve for cos^2 subtract sin^2 both sides what od you get ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no subtract sin^2 both sides so should be 1sin^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\huge\rm \frac{ 2sincos }{ \cos(1cos^2) }\] replace cos^2 by 1sin^2\[\huge\rm \frac{ 2sincos }{ \cos(1\color{Red}{}(1\sin^2))}\] distribute (1sin^) by negative sign \[\huge\rm \frac{ 2sincos }{ cos(11+\sin^2) }\] 11=0 so \[\huge\rm \frac{ 2sincos }{ \cos \times \sin^2 }\]now divide

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes \[ \frac{ 2 }{ \sin} = 2 \times \frac{ 1 }{ \sin }= ?\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright you can solve it in 5 minutes i found it easy method but there is another way to verify i really want to show that one too

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1@Loser66 please show ur work :P that was very easy

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1You do it by yourself. You know it, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1\(\dfrac{sec}{csc cot}\dfrac{sec}{csc +cot}=sec(\dfrac{1}{csccot}\dfrac{1}{csc+cot})\) \(sec(\dfrac{csc+cot}{(csccot)(csc+cot)}\dfrac{csccot}{(csccot)(csc+cot})\) =\(sec(\dfrac{csc+cotcsc+cot}{csc^2cot^2})\) And we know that \(csc^2cot^2=1\) hence it is \(sec(2cot)= 2\dfrac{1}{\cancel{cos}}\dfrac{\cancel{cos}}{sin}= 2csc\)
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