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anonymous

  • one year ago

Help will medal and fan directness pls not a lot of time For the transformation T, what is T-1? T : (x, y) (x + 4, y + 3) T-1: (x, y) (x - 4, y - 3) (-4x, -3y) (x + 3, y + 2)

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  1. anonymous
    • one year ago
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    If P(-2, 1) is rotated 90°, its image is (2, -1) (1, -2) (-1, -2)

  2. LynFran
    • one year ago
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    using matrix 90 degree rotation is \[\left[\begin{matrix}0 & -1 \\ 1 & 0\end{matrix}\right]*\left(\begin{matrix}-2 \\ 1\end{matrix}\right)\]

  3. anonymous
    • one year ago
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    so its c??

  4. LynFran
    • one year ago
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    we get \[\left(\begin{matrix}0*-2+(-1)*1 \\ 1*(-2)+0*1\end{matrix}\right)\]

  5. anonymous
    • one year ago
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    ok i think im confused

  6. LynFran
    • one year ago
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    \[\left(\begin{matrix}0-1 \\ -2+0\end{matrix}\right)\]

  7. anonymous
    • one year ago
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    so c? thats wat im thinking

  8. LynFran
    • one year ago
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    i just multiply out using matrix multiplication and yes \[\left(\begin{matrix}-1 \\ -2\end{matrix}\right)\]

  9. anonymous
    • one year ago
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    yay thanks.. wat about the first one? i got b but idk

  10. LynFran
    • one year ago
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    is that a minus 1 or \[t _{1}\]

  11. anonymous
    • one year ago
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    t1 i beleive

  12. LynFran
    • one year ago
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    well we.... T;(x,y) (x+4, y+3) T(1); (x,y) (x+4-1, y+3-1)

  13. anonymous
    • one year ago
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    okay

  14. anonymous
    • one year ago
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    x+3) (y+2)

  15. anonymous
    • one year ago
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    ?

  16. LynFran
    • one year ago
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    yep

  17. anonymous
    • one year ago
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    ohhh thank you!!!

  18. LynFran
    • one year ago
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    welcome

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