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ksaimouli

  • one year ago

inequality graph

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  1. ksaimouli
    • one year ago
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    2x+y<8 x≥4

  2. ksaimouli
    • one year ago
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    |dw:1439658954824:dw|

  3. ksaimouli
    • one year ago
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    Y< -2x +8 x>= 4

  4. ksaimouli
    • one year ago
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    |dw:1439659065625:dw|

  5. ksaimouli
    • one year ago
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    |dw:1439659175634:dw|

  6. ksaimouli
    • one year ago
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    Is that right?

  7. ganeshie8
    • one year ago
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    \(\large x\ge 4\) |dw:1439659208298:dw|

  8. ganeshie8
    • one year ago
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    |dw:1439659434315:dw|

  9. ganeshie8
    • one year ago
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    that light blue represents `y< -2x +8`

  10. ganeshie8
    • one year ago
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    whats the common region ?

  11. ksaimouli
    • one year ago
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    at intersection (4,0)

  12. ganeshie8
    • one year ago
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    no, the solution is not just a point the solution is the entire common region

  13. ganeshie8
    • one year ago
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    |dw:1439659748987:dw|

  14. ganeshie8
    • one year ago
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    the entire purple region is the solution

  15. ksaimouli
    • one year ago
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    ya, x>=4 and y<-2x. Ya, I know that having hard time to express it

  16. ganeshie8
    • one year ago
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    x>=4 and y<-2x+8 yes looks good, the light blue above is a "strict inequality", meaning the boundary line on that side is not part of solution

  17. ksaimouli
    • one year ago
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    Thank you, one more question 3x-2y>8 -2y+3x<12

  18. ksaimouli
    • one year ago
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    they have same slopes so they are parallel lines, therefore no solution

  19. ganeshie8
    • one year ago
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    lets see..

  20. ganeshie8
    • one year ago
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    |dw:1439661088244:dw|