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ksaimouli
 one year ago
inequality graph
ksaimouli
 one year ago
inequality graph

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ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439658954824:dw

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439659065625:dw

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439659175634:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2\(\large x\ge 4\) dw:1439659208298:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439659434315:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2that light blue represents `y< 2x +8`

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2whats the common region ?

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1at intersection (4,0)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2no, the solution is not just a point the solution is the entire common region

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439659748987:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2the entire purple region is the solution

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1ya, x>=4 and y<2x. Ya, I know that having hard time to express it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2x>=4 and y<2x+8 yes looks good, the light blue above is a "strict inequality", meaning the boundary line on that side is not part of solution

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1Thank you, one more question 3x2y>8 2y+3x<12

ksaimouli
 one year ago
Best ResponseYou've already chosen the best response.1they have same slopes so they are parallel lines, therefore no solution

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439661088244:dw