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- mathmath333

Probablity question

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- mathmath333

Probablity question

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- mathmath333

In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded.
What is the probability of not getting a prize if you buy (a) one ticket (b) two
tickets (c) 10 tickets

- Nnesha

lol 100% of not getting a prize for meh :P
bad luck :P

- welshfella

P(winning with one ticket) = 10/1000 = 0.001

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- mathmath333

so (a.) not winning a ticket =990/1000 ?

- welshfella

9990/10.000 = 0.999

- mathmath333

but
1-10/1000=990/1000

- mathmath333

u earlier said P(winning with one ticket) = 10/1000

- welshfella

its 10 over 10 thousand

- welshfella

yea that was a mistake should be 10 / 10,000

- mathmath333

ok

- sohailiftikhar

yes there is a probability

- sohailiftikhar

it's c

- sohailiftikhar

probability not getting prize is 10/10,000

- kropot72

If you buy 2 tickets, the probability of not getting a prize is given by
\[\large \frac{9990C2}{10000C2}=0.998\]
If you buy 10 tickets, the probability of not getting a prize is given by
\[\large \frac{9990C10}{10000C10}=0.99\]

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