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mathmath333

  • one year ago

Probablity question

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  1. mathmath333
    • one year ago
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    In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets

  2. Nnesha
    • one year ago
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    lol 100% of not getting a prize for meh :P bad luck :P

  3. welshfella
    • one year ago
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    P(winning with one ticket) = 10/1000 = 0.001

  4. mathmath333
    • one year ago
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    so (a.) not winning a ticket =990/1000 ?

  5. welshfella
    • one year ago
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    9990/10.000 = 0.999

  6. mathmath333
    • one year ago
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    but 1-10/1000=990/1000

  7. mathmath333
    • one year ago
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    u earlier said P(winning with one ticket) = 10/1000

  8. welshfella
    • one year ago
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    its 10 over 10 thousand

  9. welshfella
    • one year ago
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    yea that was a mistake should be 10 / 10,000

  10. mathmath333
    • one year ago
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    ok

  11. sohailiftikhar
    • one year ago
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    yes there is a probability

  12. sohailiftikhar
    • one year ago
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    it's c

  13. sohailiftikhar
    • one year ago
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    probability not getting prize is 10/10,000

  14. kropot72
    • one year ago
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    If you buy 2 tickets, the probability of not getting a prize is given by \[\large \frac{9990C2}{10000C2}=0.998\] If you buy 10 tickets, the probability of not getting a prize is given by \[\large \frac{9990C10}{10000C10}=0.99\]

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