anonymous
  • anonymous
graph the parabola, mark the focus and directrix on graph. y=1/32x2 help please?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Idk how to graph parabolas
anonymous
  • anonymous
@LynFran
anonymous
  • anonymous
@bullkidd

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anonymous
  • anonymous
@Vocaloid
anonymous
  • anonymous
do you have answer choices?
anonymous
  • anonymous
no i need to graph it.
anonymous
  • anonymous
the vertex is (m,k) and p is the distance to both the focus AND the directrix along the axis of symmetry from the vertex (in opposite direction). (focus is in the same direction as the sign of p)
LynFran
  • LynFran
http://www.regentsprep.org/regents/math/algebra/ac4/lpara.htm
anonymous
  • anonymous
y= 1/32 x^2 =32y = x^2 =4(8)y = x^2
anonymous
  • anonymous
so given the vertex is at (0,0) and the axis of symmetry is x=0 then: the focus is (0,8) directrix is y = -8
anonymous
  • anonymous
what does this look like on a graph? i did it on my calculator and its hard to tell
LynFran
  • LynFran
http://www.wolframalpha.com/input/?i=y%3D1%2F32x%5E2
anonymous
  • anonymous
thank you

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