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anonymous

  • one year ago

graph the parabola, mark the focus and directrix on graph. y=1/32x2 help please?

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  1. anonymous
    • one year ago
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    Idk how to graph parabolas

  2. anonymous
    • one year ago
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    @LynFran

  3. anonymous
    • one year ago
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    @bullkidd

  4. anonymous
    • one year ago
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    @Vocaloid

  5. anonymous
    • one year ago
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    do you have answer choices?

  6. anonymous
    • one year ago
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    no i need to graph it.

  7. anonymous
    • one year ago
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    the vertex is (m,k) and p is the distance to both the focus AND the directrix along the axis of symmetry from the vertex (in opposite direction). (focus is in the same direction as the sign of p)

  8. LynFran
    • one year ago
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    http://www.regentsprep.org/regents/math/algebra/ac4/lpara.htm

  9. anonymous
    • one year ago
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    y= 1/32 x^2 =32y = x^2 =4(8)y = x^2

  10. anonymous
    • one year ago
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    so given the vertex is at (0,0) and the axis of symmetry is x=0 then: the focus is (0,8) directrix is y = -8

  11. anonymous
    • one year ago
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    what does this look like on a graph? i did it on my calculator and its hard to tell

  12. LynFran
    • one year ago
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    http://www.wolframalpha.com/input/?i=y%3D1%2F32x%5E2

  13. anonymous
    • one year ago
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    thank you

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