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anonymous
 one year ago
Solve 32x≥12
x ≤ 2 or x ≥ 6
x ≥ 2 and x ≤ 6
x ≤ 2
x ≥ 6
anonymous
 one year ago
Solve 32x≥12 x ≤ 2 or x ≥ 6 x ≥ 2 and x ≤ 6 x ≤ 2 x ≥ 6

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0er???? what do you need ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do you got 2 and 6? @.@

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1\[32x\ge 12\]\[2x\ge 12/3\]\[2x\ge4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x>/= 2 divide by 1 x</= 2

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1\[2x\ge 4\]\[2x \ge \pm 4\]\[2x \ge 4\]and \[2x \ge 4\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1\[x \ge 42\]\[x \ge 2\]\[x \le 2\] and \[x \ge 42\]\[x \ge 6\]\[x \le 6\]

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1error shd be \[x \le2\]
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