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@Rushwr @taramgrant0543664 @sweetburger
@Photon336 I haven't done this but when I read I kinda felt it like it would be the 1st answer !
So this is what I'm thinking, little off today as I'm at work so bare with me lol So it says it is at constant pressure meaning isobaric conditions If heat is added to the system, then Q > 0. That is, during isobaric expansion/heating, positive heat is added to the gas, or equivalently, the environment receives negative heat. Restated, the gas receives positive heat from the environment. If the system rejects heat, then Q < 0. That is, during isobaric compression/cooling, negative heat is added to the gas, or equivalently, the environment receives positive heat. Restated, the environment receives positive heat from the gas. Since the sample was heated then Q>0 which would be A
That's something similar to what I argued !
When they say "The sample was heated at constant pressure" does this mean the external pressure that the piston is pushing against is constant or that they are heating it and pulling the piston out to increase the volume to maintain constant pressure?
Also, at the end, does this process do anything or am I misunderstanding: 1) Lock piston in place 2) Insulate the piston 3) Unlock piston Nothing should happen at all should it? What I mean is how is that different (if at all) from: 1) Insulate the piston Should have the same result right...? Haha I'm confused by why they did this whole last part at all.