What is the equation of a parabola with a vertex at (1, -1) and a directrix y = 4.

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What is the equation of a parabola with a vertex at (1, -1) and a directrix y = 4.

Mathematics
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yes
and i do not know this

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hello.
\[(x-h)^2=4p(y-k) \\ \text{ where the vertex is } (h,k) \]
p's sign is based on whether the vertex is above the directrix or below the directrix if the vertex is above the directrix, then p is positive. if the vertex is below the directrix, then p is negative.
now the other thing p has going for it .. is that it is the distance from the vertex to the directrix (or you can say the distance from the vertex to the focus)
so p tells us two things not just one
it helps to draw what we are given sometimes... |dw:1439673047228:dw| so the directrix is above the vertex so p is negative can you tell me how far the directrix is from the vertex
thx so much, i think the answer is \[y+1= -\frac{ 1 }{ 20 }\left( x-1 \right)^{2}\]

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