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anonymous

  • one year ago

Some solar energy systems are used to supplement the utility power company power supplied to a home such that the meter runs backward if the solar energy being generated is greater than the energy being used. With such a system, if the solar power averages 1.3 kW for a 3.0-h period and only 2.2kW times h is used during the period, what will be the change in the meter reading for this period? Formula: kW times h

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  1. anonymous
    • one year ago
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    Round to the nearest tenth if you dont care also.

  2. anonymous
    • one year ago
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    I will FAN AND MEDAL if you help :)

  3. anonymous
    • one year ago
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    @zepdrix

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