anonymous
  • anonymous
From the following circuit I get that the equivalent impedance is Z = 25 - j150 which in polar form is a vector with magnitude 152.07 at an angle of -80.53 (when the angular frequency is 500) but the answer is a vector with magnitude 158 and angle of −71.57. Have I done something wrong or is the answer incorrect?
Physics
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anonymous
  • anonymous
From the following circuit I get that the equivalent impedance is Z = 25 - j150 which in polar form is a vector with magnitude 152.07 at an angle of -80.53 (when the angular frequency is 500) but the answer is a vector with magnitude 158 and angle of −71.57. Have I done something wrong or is the answer incorrect?
Physics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
IrishBoy123
  • IrishBoy123
w= 500 Z= (25-150j) |Z|= 152.069063257 phase= -80.537677792 w= 1000 Z= (25+0j) |Z|= 25.0 phase= 0.0 w= 1500 Z= (25+83.3333333333j) |Z|= 87.0025542409 phase= 73.300755766 w= 2000 Z= (25+150j) |Z|= 152.069063257 phase= 80.537677792
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IrishBoy123
  • IrishBoy123
`IOW , i think i agree...:p

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