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anonymous
 one year ago
In an electric circuit, the reciprocal of the total capacitance of two capacitors in a series in the sum of reciprocals of the capacitances. Find the total capacitence of two capaciatances of 0.0050 F and 0.0040 F connected in series.
The total capacitance of the two capacitances is??
anonymous
 one year ago
In an electric circuit, the reciprocal of the total capacitance of two capacitors in a series in the sum of reciprocals of the capacitances. Find the total capacitence of two capaciatances of 0.0050 F and 0.0040 F connected in series. The total capacitance of the two capacitances is??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ C_{eq} }=\frac{ 1 }{ C_1 }+\frac{ 1 }{ C_2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(C_1\) and \(C_2\) are the given capacitances and \(C_{eq}\) is what you're solving for

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So can you help me get my solution to get the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do i need to divide or multipy?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you need to add the two fractions, then the answer will be the reciprocal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I get .009 when I add 0.0050 and 0.0040 together

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0put .005 in for C_1 and put .004 in for C2 so you should have \[\frac{ 1 }{ .005 }+\frac{ 1 }{ .004 }\] add this, then take the reciprocal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ 450 }\] ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now what to get my answer??
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