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anonymous

  • one year ago

In an electric circuit, the reciprocal of the total capacitance of two capacitors in a series in the sum of reciprocals of the capacitances. Find the total capacitence of two capaciatances of 0.0050 F and 0.0040 F connected in series. The total capacitance of the two capacitances is??

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  1. anonymous
    • one year ago
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    \[\frac{ 1 }{ C_{eq} }=\frac{ 1 }{ C_1 }+\frac{ 1 }{ C_2 }\]

  2. anonymous
    • one year ago
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    \(C_1\) and \(C_2\) are the given capacitances and \(C_{eq}\) is what you're solving for

  3. anonymous
    • one year ago
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    So can you help me get my solution to get the answer

  4. anonymous
    • one year ago
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    Do i need to divide or multipy?

  5. anonymous
    • one year ago
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    you need to add the two fractions, then the answer will be the reciprocal

  6. anonymous
    • one year ago
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    So I get .009 when I add 0.0050 and 0.0040 together

  7. anonymous
    • one year ago
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    put .005 in for C_1 and put .004 in for C2 so you should have \[\frac{ 1 }{ .005 }+\frac{ 1 }{ .004 }\] add this, then take the reciprocal

  8. anonymous
    • one year ago
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    \[\frac{ 1 }{ 450 }\] ?

  9. anonymous
    • one year ago
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    right

  10. anonymous
    • one year ago
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    So now what to get my answer??

  11. anonymous
    • one year ago
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    1/450 is the answer

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