## anonymous one year ago In an electric circuit, the reciprocal of the total capacitance of two capacitors in a series in the sum of reciprocals of the capacitances. Find the total capacitence of two capaciatances of 0.0050 F and 0.0040 F connected in series. The total capacitance of the two capacitances is??

1. anonymous

$\frac{ 1 }{ C_{eq} }=\frac{ 1 }{ C_1 }+\frac{ 1 }{ C_2 }$

2. anonymous

$$C_1$$ and $$C_2$$ are the given capacitances and $$C_{eq}$$ is what you're solving for

3. anonymous

So can you help me get my solution to get the answer

4. anonymous

Do i need to divide or multipy?

5. anonymous

you need to add the two fractions, then the answer will be the reciprocal

6. anonymous

So I get .009 when I add 0.0050 and 0.0040 together

7. anonymous

put .005 in for C_1 and put .004 in for C2 so you should have $\frac{ 1 }{ .005 }+\frac{ 1 }{ .004 }$ add this, then take the reciprocal

8. anonymous

$\frac{ 1 }{ 450 }$ ?

9. anonymous

right

10. anonymous

So now what to get my answer??

11. anonymous