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anonymous
 one year ago
Two forces with magnitudes of 25 and 30 pounds act on an object at angles of 10° and 100° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.
anonymous
 one year ago
Two forces with magnitudes of 25 and 30 pounds act on an object at angles of 10° and 100° respectively. Find the direction and magnitude of the resultant force. Round to two decimal places in all intermediate steps and in your final answer.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Resolve the force vectors into horizontal and vertical components first dw:1439676785822:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[F_x=F \cos \theta\] \[F_y=F \sin \theta\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then add the components in each direction to get the resultant force in that direction. The resultant force is (from the Pythagorean theorem) \[F=\sqrt{F_{x}^2+F_{y}^2}\] and the angle is \[\theta = \tan^{1} \frac{ F_y }{ F_x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Each of the forces makes a right triangle. The given force magnitudes are the hypotenuses of the triangles. You need to use the angles (10° and 100°) and the magnitudes to find the horizontal and vertical sides. dw:1439677744565:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For example the 25 lb force acts at 10°. The horizontal component is \[F_x=25 \cos 10°\] and the vertical is \[F_y=25 \sin 10°\] Do the same thing to find the components of the 30 lb force

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0fx= 30cos100deg fy=30sin100deg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now add the 2 Fx's and the 2 Fy's to get the components of the resultant force.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Fx = 25 cos 10° + 30 cos 100° Do Fy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Use this to find the magnitude \[F=\sqrt{F_{x}^2+F_{y}^2}\] and this to find the direction \[\theta = \tan^{1} \frac{ F_y }{ F_x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why am I not getting any of my answer choices? What am I doing wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0IFI=410.66 and theta=16.47

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got Fx = 19.41 N and Fy = 33.89 N \[F=\sqrt{19.41^2+33.89^2}=39.05~N\] \[\theta=\arctan \left( \frac{ 33.89 }{ 19.41 } \right)=60.2°\]
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