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anonymous
 one year ago
Do two 2D vectors that are not mutually perpendicular, constitute a pair of linearly independent vectors?
anonymous
 one year ago
Do two 2D vectors that are not mutually perpendicular, constitute a pair of linearly independent vectors?

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1https://gyazo.com/2b28c690ecdbb50476c734cfb981c183 in brief, yes, unless they are parallel. if they are parallel \(\vec u\times \vec v = 0\) so \[\left\left\begin{matrix}u_x & u_y \\ v_x & v_y\end{matrix}\right\right = 0\] as in this longer example: https://gyazo.com/a260ae04000052418719fb02795c2bf8

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1oops longer example here https://gyazo.com/58587800e65fda229fbac26f34289a0a url appears in screengrab

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you IrishBoy123. But I want you to take just one pair of two 2_D vectors that are non ortogonal and show the proof. You have taken a set of 3D vectors. I am not interested in that. I am interested only in the case where all the vectors are in one plane only. Only this case would be useful to me. P. Radhakrishnamurty

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dear sohailiftikhar. How do we prove your statement? P. Radhakrishnamurty
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