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anonymous

  • one year ago

Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.

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  1. anonymous
    • one year ago
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    177,147 88,572 88,575<---my answer 177,144

  2. pooja195
    • one year ago
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    \[\huge~\rm~a_n=a_1\times~r^{n-1}\] \[\huge~\rm~a_n=3\times~r^{n-1} \] \[\huge~\rm~a_{10}=3\times~r^9 \] \[\huge~\rm~59049=3\times~r^9\] \[\huge~\rm~59049/3=r^9\]

  3. pooja195
    • one year ago
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    \[\huge~\rm~19683=r^9\] \[\huge~\rm~\sqrt[9]{19683=r}\] From that we get r=3

  4. anonymous
    • one year ago
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    I got 2187? I think I did it wrong

  5. pooja195
    • one year ago
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    Ye you are wrong :) look at the work above

  6. anonymous
    • one year ago
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    I dont know how to type that into my calculator :( I originally just did 19683 times 1/9

  7. pooja195
    • one year ago
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    Well cacls wont be there all your life :(

  8. anonymous
    • one year ago
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    haha I suppose :)

  9. pooja195
    • one year ago
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    \[\huge~\rm~\Large S_{10} = \frac{3 (1-3^{10})}{1-3} =88572\]

  10. anonymous
    • one year ago
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    :) So I was right?

  11. pooja195
    • one year ago
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    You were off a few numbers look at your answer choices

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