anonymous
  • anonymous
Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
177,147 88,572 88,575<---my answer 177,144
pooja195
  • pooja195
\[\huge~\rm~a_n=a_1\times~r^{n-1}\] \[\huge~\rm~a_n=3\times~r^{n-1} \] \[\huge~\rm~a_{10}=3\times~r^9 \] \[\huge~\rm~59049=3\times~r^9\] \[\huge~\rm~59049/3=r^9\]
pooja195
  • pooja195
\[\huge~\rm~19683=r^9\] \[\huge~\rm~\sqrt[9]{19683=r}\] From that we get r=3

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anonymous
  • anonymous
I got 2187? I think I did it wrong
pooja195
  • pooja195
Ye you are wrong :) look at the work above
anonymous
  • anonymous
I dont know how to type that into my calculator :( I originally just did 19683 times 1/9
pooja195
  • pooja195
Well cacls wont be there all your life :(
anonymous
  • anonymous
haha I suppose :)
pooja195
  • pooja195
\[\huge~\rm~\Large S_{10} = \frac{3 (1-3^{10})}{1-3} =88572\]
anonymous
  • anonymous
:) So I was right?
pooja195
  • pooja195
You were off a few numbers look at your answer choices

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