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help_people

  • one year ago

A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H(t) = −16t2 + vt + s, approximately how long will it take the firecracker to hit the ground? Eight seconds Nine seconds 10 seconds 11 seconds

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  1. help_people
    • one year ago
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    @LiveLaughDie @Nnesha @pooja195

  2. sohailiftikhar
    • one year ago
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    what is s?

  3. help_people
    • one year ago
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    im not sure @sohailiftikhar

  4. sohailiftikhar
    • one year ago
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    it should be some constant value like 5,3 etc u checked the statement clearly ?

  5. sohailiftikhar
    • one year ago
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    take is 5 ..now out height H=0 to find the time 0=-16t^2+vt+5

  6. sohailiftikhar
    • one year ago
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    now 16t^2-vt=5 put value of v from given data v=110fet/sec 16t^2-110t=5 divide whole equation with 16 to get simplest form

  7. help_people
    • one year ago
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    16t^2=5+110 16T^2=115 is tis correct?

  8. sohailiftikhar
    • one year ago
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    no where is the t with 110 ?

  9. help_people
    • one year ago
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    ? could you just show me for my understudying @sohailiftikhar

  10. sohailiftikhar
    • one year ago
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    just find the value of t from the equation which i gave you ignor negative value and get +ve value that will be the answer

  11. help_people
    • one year ago
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    t=2.680951

  12. help_people
    • one year ago
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    @sohailiftikhar

  13. sohailiftikhar
    • one year ago
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    did u do your work correctly ? what two values you have got ? for t

  14. help_people
    • one year ago
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    -2.680951

  15. help_people
    • one year ago
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    there ya goooo @sohailiftikhar

  16. sohailiftikhar
    • one year ago
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    ok it's correct

  17. help_people
    • one year ago
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    ok I'm still not sue what the answer is :/ @sohailiftikhar

  18. sohailiftikhar
    • one year ago
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    lol we are not sure about s which we taken as 5 ..so take it easy it's 2 sec

  19. help_people
    • one year ago
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    that not one of the answers :( @sohailiftikhar

  20. sohailiftikhar
    • one year ago
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    so what is answer ?O.o

  21. help_people
    • one year ago
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    10? @sohailiftikhar

  22. sohailiftikhar
    • one year ago
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    lol what ? no it can be possible it only can 2 or near it your answer is correct i'm sure ..from where u get this huh ?

  23. help_people
    • one year ago
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    here are the options: Eight seconds Nine seconds 10 seconds 11 seconds

  24. Nnesha
    • one year ago
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    setup the equation when it hits the ground h(t)=0 n v=110 and s=150 now plug in the numbers and solve the qudratic equation

  25. help_people
    • one year ago
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    ok

  26. help_people
    • one year ago
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    so im solving for s?

  27. Nnesha
    • one year ago
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    no solve for t they already gave you v and s value

  28. help_people
    • one year ago
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    what are they ?

  29. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Nnesha setup the equation when it hits the ground h(t)=0 n v=110 and s=150 now plug in the numbers and solve the qudratic equation \(\color{blue}{\text{End of Quote}}\) read this

  30. help_people
    • one year ago
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    ook so what would the formula be to solve for t ?

  31. Nnesha
    • one year ago
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    \[\huge\rm \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] quadratic formula

  32. Nnesha
    • one year ago
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    a , b ,c values are \[\huge\rm Ax^2+Bx+C=0\] A= leading coefficient b=middle term c= constant term

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