I guess i've done problems like this in the past but I'm struggling with this one:-
The polynomial Q(x) leaves remainder 4 when divided by x - 1, and remainder 8 when divided by x + 1. The remainder when Q(x) is divided by x^2 - 1 is
A 32
B -4x + 9
C -4x - 7

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obviously Q(1) = 4 and Q(-1) = 8 by the remainder theorem

find the two values of x

x^2-1=(x-1)(x+1)
so x=1
and x=-1 put one by one in equation

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