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obviously Q(1) = 4 and Q(-1) = 8 by the remainder theorem

find the two values of x

x^2-1=(x-1)(x+1)
so x=1
and x=-1 put one by one in equation

so the reminder is 32

I dont follow that...

as given in data reminder for (x-1)=4 and for (x+1)=8
so for x^2-1=(x-1)(x+1)=4*8=32

now get it ?

I don't think that's correct.

I'd dont think this is particularly different - I'm just missing something

*

O.o so what you think huh ? It is correct bro

so you just confused get calm and think on it for a minute

I dont' know - but I don't think your logic is correct

I'm going to look up the answer . I am confused - you are right there!! lol

its -4x + 9

yea! go an look the answer perhaps then you will believe on my answer

no way it can't be

take a screen short

I'm helping my grandson with his maths revision. Well that's the answer in the book.

I haven't got a scanner

it's very simple .. ok tell me how they get 4 when they divide equation by (x-1) huh ?

ok ganesh is here he can justify better now

4 is the remainder and = q(1)

^

right

for example, (x^5+2x+1)/(x^2-1) gives a remainder that looks like \(ax+b\) yes ?

right

similarly (x^100 + x+1)/(x^10 + 1) gives a remainder that looks like \(ax^9+bx^8+\cdots\)

the degree of remainder is always one less than the degree of bottom

so the remainder in this case must be of the form ax + b?

right, so lets suppose
\[Q(x) = F(x)*(x^2-1)+\color{red}{ax+b}\]
our goal is to find that red part

ok

since we know that \(Q(1)=4\) and \(Q(-1)=8\), plug them in and get two equations

for that, we may think that the coefficient of x is 0 @sohailiftikhar

thats really clever Thanx ganesh

np, im getting the remainder is \(-2x+6\)
looks the options are wrong

yes i got that too
b = 6 ans a = -2

I'll just recheck the answer in the book

lol

Yes thats the answer in the book. Well mistakes are made

happens... our method is pretty robust and straightforward, nothing that could go wrong..

from which grades book u got that problem bro ?

lol ok

Open study is a great place to study . There is a wealth a talent here.

* wealth of talent

yes:)